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Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

A) Rs. 258	B) Rs. 358
C) Rs. 458	D) Rs. 558

Answer & Explanation Answer: D) Rs. 558

Explanation:

Area to be plastered = $[2 (l + b) \times h] + (l \times b)$

= $[2 (25 + 12) \times 6] + (25 \times 12) = 744 s q . m$

Cost of plastering = $744 \times \frac{75}{100} = R s . 558$

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Q:

An error of 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is

A) 4.04%	B) 5.04%
C) 6.04%	D) 7.04%

Answer & Explanation Answer: A) 4.04%

Explanation:

100 cm is read as 102 cm

a = 100 x 100 sq.cm and b = 102 x 102 sq.cm

then, Increase in area = [ (102 x 102) - (100 x 100) ] sq.cm

percentage error = $\frac{404}{100 * 100} * 100$ = 4.04%

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Q:

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

A) a	B) a>b
C) a=b	D) none

Answer & Explanation Answer: B) a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm

then perimeter of square = perimeter of rectangle

area of square = 16 sq.cm

area of rectangle = 12 sq.cm

Hence a >b

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Q:

A square and rectangle have equal areas. If their perimeters are p and q respectively. Then

A) p	B) p>q
C) p=q	D) none of these

Answer & Explanation Answer: A) p
Explanation:

square and a rectangle with equal areas will satisfy the
relation p < q

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Q:

A man walking at the speed of 4 kmph crosses a square field diagonally in 3 meters.The area of the field is

A) 10000	B) 20000
C) 30000	D) 40000

Answer & Explanation Answer: B) 20000

Explanation:

speed of the man = 4 x (5/18) m/sec = 10/9 m/sec

time taken = 3 x 60 sec = 180 sec

length of diagonal = speed x time = (10/9) x 180 = 200m

Area of the field = (1/2) x (dioagonal)²

= (1/2) x 200 x 200 sq.m = 20000sq.m

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Q:

A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?

A) 10%	B) 20%
C) 30%	D) 40%

Answer & Explanation Answer: C) 30%

Explanation:

let the side of the square be x meters
length of two sides = 2x meters
diagonal = $\sqrt{2 x}$ = 1.414x m

saving on 2x meters = .59x m

saving % = $\frac{0.59 x}{2 x} * 100$ %

= 30% (approx)

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Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Q:

A particle which is similar to electron is

A) positron	B) beta particle
C) photon	D) mason

Answer & Explanation Answer: B) beta particle

Explanation:

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