Q:

What is the equation of the line passing through the point (-1,3) and having x-intercept of 4 units?

A) 3x - 5y = 12 B) 3x + 5y = 12
C) 3x + 5y = -12 D) 3x - 5y = -12
 
Answer & Explanation Answer: B) 3x + 5y = 12

Explanation:
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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT

0 1481
Q:

Direction: What value should come in place of the question mark (?) in the following question?

12.5×14÷8.75+42=50+?

A) 18 B) 12
C) 32 D) 42
 
Answer & Explanation Answer: B) 12

Explanation:

By replacing the “?” with “x”

(12.5×14÷8.75) x (100/100) + 42 = 50 + X

(125*140)/875 + 42 = 50 + X

140/7 + 42 = 50 + X

20 + 42 = 50 + X

62 = 50 + X

X = 62 - 50

X = 12

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Exam Prep: AIEEE , Bank Exams , GATE

1 54559
Q:

Directions: What value should come in place of question mark (?) in the following question?

150% of 460+24% of 650=?

A) 854 B) 846
C) 895 D) 825
 
Answer & Explanation Answer: B) 846

Explanation:

(150 x 460)/100 + (24 x 650)/100

= 690+156

= 846

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Exam Prep: AIEEE , Bank Exams , GATE

0 61938
Q:

Direction: What will come in place of the question mark (?) in the following question?

504÷42x7-63+28 = ?

A) 72 B) 48
C) 62 D) 38
 
Answer & Explanation Answer:

Explanation:

504/42 × 7 - 63 + 28 = 84 – 63 + 28 = 49

Hence option 5 is correct.

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0 48474
Q:

Direction: What value should come in place of the question mark (?) in the following question?

534.596 + 61.472 - 496.708 = ? + 27.271

A) 126.631  B) 62.069
C) 72.089 D) 132.788
 
Answer & Explanation Answer: C) 72.089

Explanation:

534.596 + 61.472 – 496.708 = ? + 27.271

596.068 – 496.708 = ? + 27.271

? = 99.36 – 27.271

? = 72.089.

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Exam Prep: AIEEE , Bank Exams , GATE

0 51312
Q:

Directions: What value should come in place of question mark (?) in the following question?

69÷3×0.85+24.5-13.8=?

A) 31.75  B) 30.25 
C) 28.95  D) 35.25 
 
Answer & Explanation Answer: B) 30.25 

Explanation:

= (69x85/3x100) + 10.7

= 30.25.

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Exam Prep: AIEEE , Bank Exams , GATE

0 55854
Q:

If tanA - cotA = x, then value of x is?

A) (1 + 2cos2A)/(sinA cosA) B) (sinA cosA)/(1 - 2cos2A)
C) (sinA cosA)/(1 + 2cos2A) D) (1 - 2cos2A)/(sinA cosA)
 
Answer & Explanation Answer: D) (1 - 2cos2A)/(sinA cosA)

Explanation:
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Exam Prep: AIEEE , Bank Exams , CAT

0 1797
Q:

Two items A and B have equal cost price. Item A is sold at 40% profit and item B is sold at an amount 20% less than the selling price of item A. If the total profit is 156 Rs then find the cost price of A.

A) Rs. 300 B) Rs. 350
C) Rs. 400 D) Rs. 450
 
Answer & Explanation Answer: A) Rs. 300

Explanation:

Let the cost price of A as well as B is 100 Rs.
Then, ATQ:
Selling Price of A = 100+40 = 140
And Selling Price of B = 140 - (140*0.2) = 140 - 28 = 112
Total selling price = 140+112 = 252 Rs.
Total Cost price = Rs. 200
So by taking cost price = 100 Rs.
Total profit = 52 Rs.
Total profit will be Rs. 156 when cost price = (100/52)*156 = Rs. 300.

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

3 3994