Let the second & third numbers are 2x & 3x respectively.
ATQ,
5x*6x = 4320
30*x*x = 4320
x*x = 144
x=12
Hence, second number = 5x = 5*12 = 60
Third number = 6x = 6*12 = 72
Ratio of first & second number = ¾
Hence, first number = ( ¾)*60 = 45
Sum of these 3 numbers = 60+72+45 = 177

Let the speed of boat in still water is ‘x’ km/hr & that of stream is ‘y’ km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.

[(X+1400)*8*2/100] - [(X*8*1)/100]= 240
0.16X + 14*16 - 0.08X = 240
0.08X = 240 - 224
0.08X = 16
X = Rs. 200

Let the present ages of A & B to be ‘a’ & ‘b’ respectively.
Hence, 2 years ago, their ages must have been (a-2) & (b-2) respectively.
Average of their ages at that time = 26
Hence,
[(a-2)+(b-2)]/2 = 26
(a-2)+(b-2) = 52
a+b = 56
Age of A, 5 year hence = 40 years
Hence, (a+5) = 40
a = 35 years
Hence, b = 56 - 35 = 21 years
B = (C-5)
Hence, C = 21+5 = 26 years
Age difference between A & C = 35 - 26 = 9 years.

X+Y+Z = 24*3 = 72 X:Y = 2:3 (Given)
Let ‘X’ to be 2a & ‘Y’ to be 3a
X+Y = 60 (Given)
2a+3a = 60
5a = 60
a = 12
Hence, X = 24 & Y = 36
From equation (1)...
Z = 72 - 60
Z = 12
Hence, X - Z = 24-12 = 12.