Q:
Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails
Answer & Explanation
Answer: D) 1/2
Explanation: S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }
=> n(S) = 8
E = { HHH, HHT, HTH, THH }
=> n(E) = 4
P(E) = 4/8 = 1/2
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