Questions

F-F = 4 - 4 = 0

Ca-F = 4 - 1 = 3.0

H-F = 4 - 2.2 = 1.8

Na-F = 4 - 0.93 = 3.07

Hence, the highest electronegativity difference is in Na-F.

3 – Hexanol:

There is no alcohol stretch present in the spectrum. Therefore, the above structure is not suitable for the given spectrum.

Trans – 4 – octene:

There is no vinyl bending present in the spectrum. Therefore, the above structure is not suitable for the given spectrum.

1, 5 – hexadiene:

The vinyl bending and other stretches were matched with the above structure.

Hence, the c = c stretch, vinyl bending and stretch were matched with the above structure.

Therefore, the given spectrum belongs to 1, 5 – hexadiene.