6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Select the missing number based on the given related pair of numbers.

158 : 384 :: 140 : ___

A) 347	B) 346
C) 348	D) 349

Answer & Explanation Answer: C) 348

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

9 32988

Q:

In the following question, select the odd word from the given alternatives.

A) Ball	B) Bat
C) Wickets	D) Ground

Answer & Explanation Answer: D) Ground

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 32950

Q:

If 15% of x = 20% of y, then x:y is ___?

A) 4:3	B) 5:4
C) 4:5	D) 3:4

Answer & Explanation Answer: A) 4:3

Explanation:

Given 15% of x = 20% of y

=> 15x = 20y

=> x/y = 20/15

=> x : y = 4 : 3

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

77 32906

Q:

A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

A) 100 m	B) 75 m
C) 25 m	D) 50m

Answer & Explanation Answer: A) 100 m

Explanation:

When B runs 25 m, A runs 45/2 m

When B runs 1000 m, A runs (45/2*1/25*1000)m = 900 m.

B beats A by 100 m.

Report Error

View Answer Report Error Discuss

Filed Under: Races and Games

44 32831

Q:

The difference between the simple interest on a certain sum at the rate of 10%per annum for 2 years and compound interest which is compounded every 6 months is Rs.124.05. what is the principal sum

A) Rs.6000	B) Rs.8000
C) Rs.12000	D) none of these

Answer & Explanation Answer: B) Rs.8000

Explanation:

Compound Interest on P at 10% for 2 years when interest is compounded half-yearly

= $P {(1 + \frac{\frac{R}{2}}{100})}^{2 T} - P = P {(1 + \frac{1}{20})}^{4} - P = P {(\frac{21}{20})}^{4} - P$

Simple Interest on P at 10% for 2 years = $\frac{P R T}{100} = \frac{P \times 10 \times 2}{100} = \frac{P}{5}$

Given that difference between compound interest and simple interest = 124.05

$P * {(\frac{21}{20})}^{4} - P - \frac{P}{5} = 124.05$

=> $P [{(\frac{21}{20})}^{4} - 1 - \frac{1}{5}] = 124.05$

P=8000

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

61 32810

Q:

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?

A) Data inadequate	B) 8 units
C) 12 units	D) None of these

Answer & Explanation Answer: A) Data inadequate

Explanation:

One of AB, AD and CD must have given.

So, the data is inadequate.

Report Error

View Answer Report Error Discuss

Filed Under: Height and Distance

25 32673

Q:

The ratio of efficiency of A is to C is 5:3. The ratio of number of days taken by B is to C is 2:3. A takes 6 days less than C, when A and C completes the work individually. B and C started the work and left after 2 days. The number of days taken by A to finish the remaining work is:

A) 4.5	B) 5
C) 6	D) 9 1/3

Answer & Explanation Answer: C) 6

Explanation:

A : C

Efficiency 5 : 3

No of days 3x : 5x

Given that, 5x-6 =3x => x = 3

Number of days taken by A = 9

Number of days taken by C = 15

B : C

Days 2 : 3

Therefore, Number of days taken by B = 10

Work done by B and C in initial 2 days = $2 [\frac{1}{10} + \frac{1}{15}]$ = 1/3

Thus, Rest work =2/3

Number of days required by A to finish 2/3 work = (2/3) x 9 = 6 days

Report Error

View Answer Report Error Discuss

Filed Under: Time and Work

81 32598

Q:

At what rate of compound interest per annum will a sum of rs.1200 becomes rs.1348.32 in 2 years

A) 66%%	B) 6.5%
C) 7%	D) 7.5%

Answer & Explanation Answer: A) 66%%

Explanation:

rate=r%

1200 (1+r/100)^2=1348.32

r=6%

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Analyst

42 32563

Quantitative Aptitude - Arithmetic Ability Questions

Quick Links