6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident

A) 30/100	B) 35/100
C) 45/100	D) 50/100

Answer & Explanation Answer: B) 35/100

Explanation:

Let A = Event that A speaks the truth

B = Event that B speaks the truth

Then P(A) = 75/100 = 3/4

P(B) = 80/100 = 4/5

P(A-lie) = $1 - \frac{3}{4}$ = 1/4

P(B-lie) = $1 - \frac{4}{5}$ = 1/5

Now, A and B contradict each other =[A lies and B true] or [B true and B lies]

= P(A).P(B-lie) + P(A-lie).P(B)

= $(\frac{3}{5} * \frac{1}{5}) + (\frac{1}{4} * \frac{4}{5}) = \frac{7}{20}$

= $(\frac{7}{20} * 100)$ = 35%

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64 29480

Q:

Select the figure which does NOT belong to the group.

A) C	B) B
C) A	D) D

Answer & Explanation Answer: C) A

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

2 29436

Q:

Consider the following grouped frequency distribution:

x f

0-10 8

10-20 12

20-30 10

30-40 p

40-50 9

If the mean of the above data is 25.2, then what is the value of p?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: C) 11

Explanation:

Mean = (sum of fixi/ (sum of f) = (8*5 + 12*15 + 10*25 + P*35 +9*45) / (8+12+10+P+9) = 25.2

(875 + 35P)/(39+P) = 25.2

P = 11

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Filed Under: Average
Exam Prep: Bank Exams

0 29427

Q:

Sekar started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajeev joined him with an amount of Rs. 35,000. In 2001, Sekar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000. What will be Rajeev's share in the profit of Rs.1,50,000 earned at the end of 3 years from the start of the business in 1999?

A) Rs. 45,000	B) Rs. 50,000
C) Rs. 70,000	D) Rs. 75,000

Answer & Explanation Answer: B) Rs. 50,000

Explanation:

Sekar: Rajeev: jatin = (25000×12+35000×12+45000×12):(35000×24) : (35000×12)

= 1260000 : 840000 : 420000

= 3 : 2 : 1.

Rajeev's Share =Rs.(150000×2/6)

=Rs.50000.

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Filed Under: Partnership

30 29418

Q:

In a race, the odd favour of cars P,Q,R,S are 1:3, 1:4, 1:5 and 1:6 respectively. Find the probability that one of them wins the race.

A) 319/420	B) 27/111
C) 114/121	D) 231/420

Answer & Explanation Answer: A) 319/420

Explanation:

$P (P) = \frac{1}{4}, P (Q) = \frac{1}{5}, P (R) = \frac{1}{6}, P (S) = \frac{1}{7}$
All the events are mutually exclusive hence,

Required probability = P(P)+P(Q)+P(R)+P(S)

$\frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7}$ = $\frac{319}{420}$

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38 29265

Q:

In the following question,select the missing number from the given alternatives.

7, 26, ?, 124, 215, 342

A) 63	B) 65
C) 66	D) 67

Answer & Explanation Answer: A) 63

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 29234

Q:

Find the odd word/letters/number from the given alternatives.

A) Potato	B) Tomato
C) Ginger	D) Carrot

Answer & Explanation Answer: B) Tomato

Explanation:

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0 29147

Q:

The length of a diagonal in cm of a rectangle of length 9 cm and width 5 cm is

A) 106	B) ±106
C) 2√14	D) ±214

Quantitative Aptitude - Arithmetic Ability Questions

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