6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?

A) 4 days	B) 6 days
C) 7 days	D) 5 days

Answer & Explanation Answer: A) 4 days

Explanation:

Given that

6 men and 8 boys can do a piece of work in 10 days

26 men and 48 boys can do the same in 2 days

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

33 26135

Q:

One of the roots of the equation $x^{2} - 6 x + k = 0$ is x = 2. The other root is

A) x = -1	B) x = 4
C) x = -4	D) x = 1

Answer & Explanation Answer: B) x = 4

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 26119

Q:

Consider the following frequency distribution:

x f

8 6

5 4

6 5

10 8

9 9

4 6

7 4

What is the median for the distribution?

A) 6	B) 7
C) 8	D) 9

Answer & Explanation Answer: C) 8

Explanation:

Summation of frequencies = 6+4+5+8+9+6+4 = 42

Median = mid value = average of 21st and 22nd value

Arranging data in increasing order we get

x f

4 6

5 4

6 5

7 4

8 6

9 9

10 8

So mid value i.e 21st and 22nd value = 8

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Filed Under: Average
Exam Prep: Bank Exams

0 26051

Q:

A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg	B) 1 kg
C) 1.5 kg	D) None of these

Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then

$512 = K {(1 - \frac{1}{5})}^{4}$ $[∵ 20 % = \frac{20}{100} = \frac{1}{5}]$

or

$512 = K {(\frac{4}{5})}^{4}$

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg

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Filed Under: Alligation or Mixture

32 26038

Q:

In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?

A) 53400	B) 17610
C) 11760	D) 45000

Answer & Explanation Answer: C) 11760

Explanation:

Required number of ways = $(8 C_{5} * 10 C_{6})$ = $(8 C_{3} * 10 C_{4})$ = 11760

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Filed Under: Permutations and Combinations

25 25996

Q:

If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM ?

A) 32	B) 24
C) 72	D) 36

Answer & Explanation Answer: A) 32

Explanation:

The 5 letter word can be rearranged in 5!=120 Ways without any of the letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _.
The remaining 3 letters can be rearranged in 3!=6 Ways. i.e. 6 words exist that start with CA.

The next word starts with CH and then A, i.e., CHA _ _.
The first of the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24+6+2= 32

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Filed Under: Permutations and Combinations

17 25963

Q:

The population of a town was 3600 three years back. It is 4800 right now. What will be the population three years down the line, if the rate of growth of population has been constant over the years and has been compounding annually?

A) Rs.600	B) Rs,6400
C) Rs.6500	D) Rs.6600

Answer & Explanation Answer: B) Rs,6400

Explanation:

The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.

Therefore, the rate of growth for three years has been constant.

The rate of growth during the next three years will also be the same.

Therefore, the population will grow from 4800 by $4800 * \frac{1}{3}$ = 1600

Hence, the population three years from now will be 4800 + 1600 = 6400

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

30 25943

Q:

A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ?

A) 4.58 kms	B) 6.35 kms
C) 5.76 kms	D) 5.24 kms

Answer & Explanation Answer: C) 5.76 kms

Explanation:

Speed in still water = 6 kmph

Stream speed = 1.2 kmph

Down stream = 7.2 kmph

Up Stream = 4.8 kmph

x/7.2 + x/4.8 = 1

x = 2.88

Total Distance = 2.88 x 2 = 5.76 kms

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

37 25928

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