6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is :

A) 12	B) 24
C) 36	D) 48

Answer & Explanation Answer: B) 24

Explanation:

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2

Sum of digits = x + (x + 2) = 2x + 2.

(11x + 2) (2x + 2) = 144

=> 22x^2+26x-140=0

=> (x - 2)(11x + 35) = 0

=> x = 2

Hence, Required Number = 11x + 2 = 24

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Filed Under: Problems on Numbers

28 24616

Q:

Select the wrong number from the given series?

6, 12, 20, 32, 42, 56, 72

A) 32	B) 20
C) 72	D) 56

Answer & Explanation Answer: A) 32

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 24592

Q:

A 6% stock yields 8% . The market value of the stock is :

A) Rs.48	B) Rs.75
C) Rs.96	D) Rs.133.33

Answer & Explanation Answer: B) Rs.75

Explanation:

For an income of Rs. 8, investment = Rs. 100.

For an income of Rs 6, investment =Rs. (100/8*6) = Rs. 75

Market value of Rs. 100 stock = Rs. 75.

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Filed Under: Stocks and Shares

28 24576

Q:

The principal that amounts to Rs.4913 in 3 years at $4 \frac{1}{3}$ % per annum compound interest compounded annually is

A) Rs.3096	B) Rs.4076
C) Rs.4085	D) Rs.4096

Answer & Explanation Answer: D) Rs.4096

Explanation:

principal = $A = 4913, T = 3, R = 4 \frac{1}{3}$

$P = {\frac{A}{(\frac{1 + R}{100})}}^{T}$

= Rs.4096

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Filed Under: Compound Interest
Exam Prep: GRE

30 24570

Q:

Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in

A) 6 days	B) 12 days
C) 4 days	D) 3 days

Answer & Explanation Answer: D) 3 days

Explanation:

Let x men can do the in 12 days and the required number of days be z

More men, Less days [Indirect Proportion]

Less work, Less days [Direct Proportion ]

$\begin{array}{r} \begin{matrix} m e n & 2 x & : & x \end{matrix} \\ \begin{matrix} w o r k & 1 & : & \frac{1}{2} \end{matrix} \end{array}\} : : 12 : z$

$∴ (2 x \times 1 \times z) = (x \times \frac{1}{2} \times 12)$

$\Rightarrow z = 3$

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Filed Under: Chain Rule

28 24559

Q:

Read the data given and answer the following questions

In a class of 60 students:

42 like Maths,

32 like English,

12 like neither Maths nor English

Students who like only Maths forms what percentage of the total number of students in the class?

A) 26.67%	B) 24.22%
C) 28.80%	D) 32.82%

Answer & Explanation Answer: A) 26.67%

Explanation:

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Filed Under: Percentage
Exam Prep: Bank Exams

0 24549

Q:

The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.

A) 27 and 23	B) 24 and 23
C) 25 and 23	D) 22 and 23

Answer & Explanation Answer: A) 27 and 23

Explanation:

Let the two parallel sides of the trapezium be a cm and b cm.

Then, a - b = 4

And, $\frac{1}{2} \times (a + b) \times 19 = 475 = > (a + b) = 50$

Solving (i) and (ii), we get: a = 27, b = 23.

So, the two parallel sides are 27 cm and 23 cm.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

23 24481

Q:

On what dates of July.2004 did Monday fall?

A) 6th,10th,21st,30th	B) 12th,7th,19th,28th
C) 5th,10th,24th,17th	D) 5th, 12th, 19th, 26th

Answer & Explanation Answer: D) 5th, 12th, 19th, 26th

Explanation:

Let us find the day on 1st July, 2004.

2000 years have 0 odd day. 3 ordinary years have 3 odd days.

Jan. Feb. March April May June July

31 + 29 + 31 + 30 + 31 + 30 + 1

= 183 days = (26 weeks + 1 day) = 1 t .

Total number of odd days = (0 + 3 + 1) odd days = 4 odd days. '

:. 1st July 2004 was 'Thursday',-,-

Thus, 1st Monday in July 2004 _as on 5th July.

Hence, during July 2004, Monday fell on 5th, 12th, 19th and 26th. .

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Filed Under: Calendar

118 24421

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