Quantitative Aptitude - Arithmetic Ability Questions

P(first letter is not vowel) = 24

P(second letter is not vowel) = 13

So, probability that none of letters would be vowels is = 24×13=16

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

Let each side of the square be a. Then, area = .a2
New side =125a100=5a4. New area = 5a42 = 25a216

Increase in area = 25a216-a2=9a216
Increase% = 9a216*1a2*100 % = 56.25%.

99 = 1 x 3 x 3 x 11

101 = 1 x 101

176 = 1 x 2 x 2 x 2 x 2 x 11

182 = 1 x 2 x 7 x 13

So, divisors of 99 are 1, 3, 9, 11, 33, .99

Divisors of 101 are 1 and 101

Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176

Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.

Hence, 176 has the most number of divisors.

Let the capacity of the tank be x litres.

Then, (6x/7 - 2x/5) = 16 <=> 30x - 14x = 16*35 <=> x = 35

Let the sum be Rs. x. Then,

 C.I=x*50300*1003-x=343x216-x=127x216 

⇔127x216=1270 

x=2160 

Thus, the sum is Rs. 2160

 S.I=Rs.2160*503*3*1100=Rs 1080