6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the volume (in cub.cm) of a hemisphere of diameter 28 cm.

A) 4789.67	B) 3675
C) 2732	D) 5749.33

Answer & Explanation Answer: D) 5749.33

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

1 22474

Q:

In the following question, select the related number from the given alternatives.

8 : 27 : : 64 : ?

A) 190	B) 144
C) 125	D) 72

Answer & Explanation Answer: C) 125

Explanation:

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Filed Under: Ratios and Proportions

0 22443

Q:

What was the day of the week on 16th August, 1947?

A) Sunday	B) Monday
C) Saturday	D) Thursday

Answer & Explanation Answer: C) Saturday

Explanation:

15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )

Counting of odd days:

1600 years have 0 odd day. 300 years have 1 odd day.

47 years = (11 leap years + 36 ordinary years)= [(11 x 2) + (36 x 1) ]odd days = 58 odd days = 2 odd days.

Jan Feb Mar Apr May Jun Jul Aug.

31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3,

Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days.

Hence, the required day was 'Saturday'.

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Filed Under: Calendar

86 22438

Q:

∆DEF is right angled at E. If m∠F = 45°, then find the value of (tanD - √3/2).

A) -√3/2	B) -1/2√3
C) (2-√3)/2	D) (3√3-1)/3

Answer & Explanation Answer: C) (2-√3)/2

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 22423

Q:

A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is:

A) 5%	B) 8%
C) 12%	D) 15%

Answer & Explanation Answer: C) 12%

Explanation:

S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.

S.I. for 5 years = Rs. $\frac{2205}{3} \times 5$ = Rs.3675

Principle = Rs.(9800-3675) = Rs.6125

Hence, Rate = $[\frac{100 \times 3675}{6125 \times 5}]$ =12%

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

18 22410

Q:

In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?

A) 1years	B) 2years
C) 3years	D) 4years

Answer & Explanation Answer: C) 3years

Explanation:

Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then,
[ 1000 (1+ (10/100))^n ] = 1331 or (11/10)^n = (1331/1000) = (11/10)^3
n = 3 years

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

39 22370

Q:

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A) 209	B) 290
C) 200	D) 208

Answer & Explanation Answer: A) 209

Explanation:

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).

Required number of ways = $(6 C_{1} * 4 C_{3}) + (6 C_{2} * 4 C_{2}) + (6 C_{3} * 4 C_{1}) + 6 C_{4}$

= $(6 C_{1} * 4 C_{1}) + (6 C_{2} * 4 C_{2}) + (6 C_{3} * 4 C_{1}) + 6 C_{2}$ = 209.

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Filed Under: Permutations and Combinations

11 22328

Q:

A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is :

A) 35/96	B) 19/90
C) 19/96	D) None of these

Answer & Explanation Answer: B) 19/90

Explanation:

$A S S I S T A N T \to A A I N S S S T T$

$S T A T I S T I C S \to A C I I S S S T T T$

Here N and C are not common and same letters can be A, I, S, T. Therefore

Probability of choosing A = $\frac{2_{C_{1}}}{9_{C_{1}}} \times \frac{1_{C_{1}}}{10_{C_{1}}}$ = 1/45

Probability of choosing I = $\frac{1}{9_{C_{1}}} \times \frac{2_{C_{1}}}{10_{C_{1}}}$ = 1/45

Probability of choosing S = $\frac{3_{C_{1}}}{9_{C_{1}}} \times \frac{3_{C_{1}}}{10_{C_{1}}}$ = 1/10

Probability of choosing T = $\frac{2_{C_{1}}}{9_{C_{1}}} \times \frac{3_{C_{1}}}{10_{C_{1}}}$ = 1/15

Hence, Required probability = $\frac{1}{45} + \frac{1}{45} + \frac{1}{10} + \frac{1}{15} = \frac{19}{90}$

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

97 22316

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