Quantitative Aptitude - Arithmetic Ability Questions

Q:

A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

A) 156 B) 166
C) 176 D) 186
 
Answer & Explanation Answer: C) 176

Explanation:

Area of the room=(544 * 374)

 

size of largest square tile= H.C.F of 544 & 374 = 34 cm

 

Area of 1 tile = (34  x  34) cm2

 

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

54 20851
Q:

Find the odd word/letters/number from the given alternatives.

(A) BCE (B) WXZ (C) MNP (D) GHK

A) A B) B
C) C D) D
 
Answer & Explanation Answer: D) D

Explanation:
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0 20850
Q:

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

A) 1677 B) 1683
C) 2523 D) 3363
 
Answer & Explanation Answer: B) 1683

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

 

 Required number is of the form 840k + 3

 

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

 

 Required number = (840 x 2 + 3) = 1683.

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Filed Under: HCF and LCM

25 20835
Q:

An accurate clock shows 7 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 3 o'clock in the afternoon?

A) 144º B) 168º
C) 180º D) 150º
 
Answer & Explanation Answer: C) 180º

Explanation:

Angle traced by the hour hand in 6 hours =360o12×6 = 180o.

 


 

 


 
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Filed Under: Clocks
Exam Prep: CAT
Job Role: Bank Clerk

41 20824
Q:

The difference between simple interest and compound interest on Rs. 1200 for one year at 10% per annum reckoned half yearly is

A) Rs.2.50 B) Rs.3
C) Rs.4 D) Rs.4.50
 
Answer & Explanation Answer: B) Rs.3

Explanation:

S.I

= Rs.(1200x10x1/100)

= Rs.120.

 

C.I

= Rs[(1200x1+5/100)² -1200]

= Rs.123. 

 

Difference

= Rs.[123-120]

= Rs. 3.

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Filed Under: Compound Interest
Exam Prep: GRE

29 20817
Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

 

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2 B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2 D) Quantity 1 ≤ Quantity 2
 
Answer & Explanation Answer: A) Quantity 1 > Quantity 2

Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ 1x-9

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = 115+110+16
⇒ Net part filled in 1 hour = 4+6+1060
⇒Net part filled in 1 hour = 2060=13
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2

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2 20781
Q:

The ratio of the father's age to the son's age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?

Answer

Let father's age be 3x and son's age be x years




Father's age after 5 years = 3x + 5 = 26 years


Son's age after 5 years = x + 5 = 12 years


 Ratio of father's and son's ages = 26 : 12 = 13 : 6


 

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Subject: Problems on Ages

89 20760
Q:

In two triangles, the ratio of the areas is 4 : 3 and the ratio of their heights is 3 : 4. Find the ratio of their bases.

A) 13:9 B) 16:9
C) 15:9 D) 14:9
 
Answer & Explanation Answer: B) 16:9

Explanation:

Let the bases of the two triangles be x and y and their heights be 3h and 4h respectively.
Then, 12×x×3h12×y×4h=43xy=43×43=169 

 

Required ratio = 16 : 9.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

24 20760