6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ?

A) 41 yrs	B) 40 yrs
C) 37 yrs	D) 33 yrs

Answer & Explanation Answer: B) 40 yrs

Explanation:

Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.

=> A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)

=> 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8

V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8

=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8

=> 10 - 20/3 = 10/12 A - 9/12 A

=> 10/3 = A/12 => A = 40.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

26 19213

Q:

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is :

A) 12	B) 137
C) 14	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let the three integers be x, x + 2 and x + 4. Then, 3x = 2 (x + 4) + 3 <=> x = 11.

Third integer = x + 4 = 15.

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Filed Under: Problems on Numbers

38 19145

Q:

A child has three different kinds of chocolates costing Rs.2, Rs.5, Rs.10. He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be atleast one chocolate of each kind?

A) 22	B) 19
C) 17	D) 15

Answer & Explanation Answer: C) 17

Explanation:

Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.

Thus, 2 x 5 + 5 x 2 =Rs.20

Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.

Thus minumum number of chocolates = 5 + 2 + 10 = 17

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Filed Under: Ratios and Proportions

48 19145

Q:

3 x 0.3 x 0.03 x 0.003 x 30 =?

A) 0.0000243	B) 0.000243
C) 0.00243	D) 0.0243

Answer & Explanation Answer: C) 0.00243

Explanation:

3 x 3 x 3 x 3 x 30 = 2430. Sum of decimal places = 6

Therefore, 3 x 0.3 x 0.03 x 0.003 x 30 = 0.002430 = 0.00243

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Filed Under: Decimal Fractions

72 19142

Q:

∆PQR is right angled at Q. If m∠P = 60 deg, then find the value of (secR + 1/2).

A) (2√2+√3)/2	B) (√3+4)/2√3
C) √3+2	D) 5/6

Answer & Explanation Answer: B) (√3+4)/2√3

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 19102

Q:

A boatman can row 3 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current ?

A) 1/3 kmph	B) 2/3 kmph
C) 1/4 kmph	D) 1/2 kmph

Answer & Explanation Answer: D) 1/2 kmph

Explanation:

Speed in upstream = Distance / Time = 3 x 60/20 = 9 km/hr.

Speed in downstream = 3 x 60/18 = 10 km/hr

Rate of current = (10-9)/2 = 1/2 km/hr.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

32 19085

Q:

If Rs.10 be allowed as true discount on a bill of Rs.110 at the end of a certain time , then the discount allowed on the same sum due at the end of double the time is

A) 18.20	B) 18.33
C) 18	D) 18.30

Answer & Explanation Answer: B) 18.33

Explanation:

Present worth = Amount - True Discount = 110 -10 = Rs.100

SI on Rs.100 for a certain time = Rs.10

SI on Rs.100 for doube the time = Rs.20

True Discount on Rs.120 = 120 - 100 = Rs.20

True Discount on Rs.110 = $(110 \times \frac{20}{120})$ = Rs.18.33

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Filed Under: True Discount

6 19076

Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

An artificial kund is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the kund at the same time during which the kund is filled by the third pipe alone. The second pipe fills the kund 5 hours faster than the first pipe and 4 hours slower than the third pipe.

Quantity 1: The time required by the first pipe?

Quantity 2: Time taken by all three pipes to fill the Kund simultaneously

A) Quantity 1 > Quantity 2	B) Quantity 1 ≥ Quantity 2
C) Quantity 1 < Quantity 2	D) Quantity 1 ≤ Quantity 2

Answer & Explanation Answer: A) Quantity 1 > Quantity 2

Explanation:

Quantity 1:
Let the first pipe alone takes x hours to fill the
tank.
⇒The second and third pipes will take (x-5) and
(x-9) hours respectively.
According to the given information:
∴ $\frac{1}{x - 9}$

⇒ (x-9)(2x-5) = x2 – 5x
⇒ 2x2 – 5x – 18x + 45 = x2 – 5x
⇒ x
2 -18x + 45 = 0
⇒ (x-15) (x-3) = 0
⇒ x = 15, 3

The first pipe can take 15 hours to fill the kund.
∵ 3 hours doesn’t satisfy the statement.
Quantity 2:
∴ Time taken by second pipe = x-5
⇒ Time taken by second pipe = 15-5 = 10hours
∴ Time taken by third pipe = x -9
⇒ Time taken by third pipe = 15- 9 = 6 hours
Now,

Net part filled in 1 hour = $\frac{1}{15} + \frac{1}{10} + \frac{1}{6}$
⇒ Net part filled in 1 hour = $\frac{4 + 6 + 10}{60}$
⇒Net part filled in 1 hour = $\frac{20}{60} = \frac{1}{3}$
∴The Kund will be full in 3/1 hours if all the pipes are opened simultaneously
Now, comparing
15 > 3
Thus, Quantity 1 > quantity 2

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

2 19053

Quantitative Aptitude - Arithmetic Ability Questions

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