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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ?

A) 14 1/2 days B) 11 days
C) 13 1/4 days D) 12 6/7 days
 
Answer & Explanation Answer: D) 12 6/7 days

Explanation:

Let 'B' alone can do the work in 'x' days

6/30 + 18/x = 1

=> x = 22.5

 

1/30 + 1/22.5 = 7/90 

=> 90/7 = 12 6/7 days

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Filed Under: Time and Work
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

29 20074
Q:

The runs scored by two batsmen over 7 matches are given below. Which batsman average was better ?

 

A) Batsman 1 - 39.3 B) Batsman 1 - 45.9
C) Batsman 1 - 43.2 D) Batsman 2 - 45.9
 
Answer & Explanation Answer: D) Batsman 2 - 45.9

Explanation:
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Filed Under: Average
Exam Prep: Bank Exams

1 20048
Q:

Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ?

A) 10 B) 18
C) 12 D) 15
 
Answer & Explanation Answer: A) 10

Explanation:

Given total rupees = 20 Rs
No. of one rupee stamps = 3
Now, remaining money = Rs. 17
With that he buys only 2 and 5 rupee stamps
Let number of Rs. 5 stamps = K
Let number of Rs. 2 stamps = L
5K + 2L = 17
K = 3, L = 1 (possible)
L = 6, K = 1 (possible)
=> But given that they are different in number so, K is not equal to 3
one rupee stamps = 3
2 two stamps = 6
5 rupee stamps = 1
Total number of stamps = 10.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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45 20037
Q:

In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ?

A) 693 B) 741
C) 528 D) 654
 
Answer & Explanation Answer: C) 528

Explanation:

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)
= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available
=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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30 20027
Q:

What will be the 20th term in the given sequence?

 

-50, -47, -44, _

 

A) -10 B) 10
C) -7 D) 7
 
Answer & Explanation Answer: D) 7

Explanation:
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Filed Under: Numbers
Exam Prep: Bank Exams

10 20002
Q:

What value should come in place of the question mark (?) in the following question?

1637 + 1832 = 452 + (?)2

A) 38 B) 42
C) 46 D) 54
 
Answer & Explanation Answer: A) 38

Explanation:

3469 = 2025+?x?
? x ?= 3469-2025
? x ?= 1444
? = 38

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 19976
Q:

From a tank of petrol , which contains 200 liters of petrol, the seller replaces each time with kerosene when he sells 40 liters of petrol(or mixture). Everytime he sells out only 40 liters of petrol (pure or impure). After replacing the petrol with kerosene 4th time, the total amount of kerosene in the mixture is

A) 81.92L B) 96L
C) 118.08L D) None of these
 
Answer & Explanation Answer: C) 118.08L

Explanation:

The amount of petrol left after 4 operations = 200×1-402004=81.92 

 

Hence the amount of kerosene = 200 - 81.92 = 118.08 liters

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Filed Under: Alligation or Mixture

24 19947
Q:

How many numbers up to 300 and 700 are divisible by 2, 3 and 7 both together ?

A) 7 B) 9
C) 11 D) 5
 
Answer & Explanation Answer: B) 9

Explanation:

LCM of 2, 3, 7 is 42.

=> (700 – 300)/42 = 9  22/42 => 9 Numbers.

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Filed Under: Numbers
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28 19942