Quantitative Aptitude - Arithmetic Ability Questions

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$$\begin{gathered} weavers 4:8} :4:x \\ days 4:8}:4:x \end{gathered}$$ 

4 x 4 x x = 8 x 8 x 4

=> x = 8*8*44*4

=> x = 16.

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12. 

We know that the sum of their ages is 50 .

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=>  x= 4

 The youngest child is 4 years old.

Given Expression = 18800470÷20 = 40÷20 = 2

x128 = 162x

Then x² = 162x128

   = Sqrt of 8² x 6² x 3²

   = 8 x 6 x 3

   x²  = 144.

 x  = 12.

Let marks obtained by S = M

R's marks = 0.80M

Q's marks = 1.25 (0.80M)

P's marks = (0.90) (1.25) (0.80M)

= 0.9M

But 0.9M = 360

M = ?

M = 400

Hence % of marks obtained by S

= 400/500 x 100 = 80%.

Let ? = p

38 x 7500/100  + p x 375/100 = 50 x 6000/100

=> 38 x 75 + 3.75p = 3000

=> 3.75p = 3000 - 2850

=> p = 150/3.75 

=> p = ? = 40

Let the numbers be 3x, 4x, 5x.

Then, their L.C.M = 60x.

So, 60x=3600 or x=60.

Therefore,  The numbers are (3 x 60), (4 x 60), (5 x 60).

Hence,required H.C.F=60

Required Sum = PW of Rs.702 due 6 months hence + PW of Rs.702 due 1 year hence 

= Rs.[ (100 x 702) / (100+(8 x 1/2)) ] + [ (100 x 702) / (100+(8 x 1)) ]  

= Rs.1325