6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two trains are running at 60 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 6 seconds. What is the length of the fast train ?

$A . 66 \frac{2}{3} m t s$

$B . 66 \frac{3}{2} m t s$

$C . 63 \frac{4}{5} m t s$

$D . 63 \frac{5}{4} m t s$

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: A) Option A

Explanation:

As Trains are moving in same direction,

Relative Speed = 60-20 = 40 kmph

--> $40 \times \frac{5}{18} = \frac{100}{9}$ m/sec

Length of Train= Speed * Time

Length = $\frac{100}{9} \times 6$

$\Rightarrow \frac{200}{3} = 66 \frac{2}{3} m t s$

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Filed Under: Problems on Trains
Exam Prep: CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

12 10824

Q:

A square and rectangle have equal areas. If their perimeters are p and q respectively. Then

A) p	B) p>q
C) p=q	D) none of these

Answer & Explanation Answer: A) p
Explanation:

square and a rectangle with equal areas will satisfy the
relation p < q

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

5 10822

Q:

What is the sum which earned interest?
I. The total simple interest was Rs. 7000 after 7 years.
II. The total of sum and simple interest was double of the sum after 5 years.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Let the sum be Rs. x.

I gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year = Rs. 1000.

Thus, I and II both are needed to get the answer.

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

3 10820

Q:

A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ?

A) 1080 cm	B) 180 m
C) 108 m	D) 118 cm

Answer & Explanation Answer: C) 108 m

Explanation:

We know the rule that,

At particular time for all object , ratio of height and shadow are same.

Let the height of the pole be 'H'

Then

$\frac{18}{8} = \frac{H}{48}$

=> H = 108 m.

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Filed Under: Height and Distance
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

19 10811

Q:

What was the day on 16th June,1993?

A) Saturday	B) Monday
C) Wednesday	D) Friday

Answer & Explanation Answer: C) Wednesday

Explanation:

16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)

Odd days in 1600 years = 0

Odd days in 300 years = 1

92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days

167 days = (23 weeks + 6 days) =6 odd days.

Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.

Given day is Wednesday.

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Filed Under: Calendar

18 10792

Q:

The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?

A) 2413 sq.m	B) 1234 sq.m
C) 4312 sq.m	D) 2143 sq.m

Answer & Explanation Answer: C) 4312 sq.m

Explanation:

Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.

$2 πs$ = 264 and $2 πl$ = 352

s = $\frac{264}{2 π}$ and l = $\frac{352}{2 π}$

Difference between the areas = $π l^{2} - π s^{2}$

= $π (\frac{176^{2}}{π^{2}} - \frac{132^{2}}{π^{2}})$

= $\frac{1762}{π} - \frac{1322}{π}$

= (176 - 132)(176 + 132) / $π$

= (44 x 308) / (22/7) = 4312 sq.m

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Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

18 10774

Q:

On what dates of April, 2001 did Wednesday fall ?

A) 1st, 8th, 15th, 22nd, 29th	B) 2nd, 9th, 16th, 23rd, 30th
C) 3rd, 10th, 17th, 24th	D) 4th, 11th, 18th, 25th

Answer & Explanation Answer: D) 4th, 11th, 18th, 25th

Explanation:

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Filed Under: Calendar

10 10771

Q:

Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?

A) 6	B) 8
C) 9	D) 10

Answer & Explanation Answer: B) 8

Explanation:

Average speed = total distance / total time

Total distance covered = 6 miles; total time = 45 minutes = 0.75 hours

Average speed = 6/ 0.75 = 8 miles/hour

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Filed Under: Height and Distance
Exam Prep: GRE

23 10763

Quantitative Aptitude - Arithmetic Ability Questions

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