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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

There are 11 True or False questions. How many ways can these be answered ?

A) 11!/2 B) 1024
C) 11! D) 2048
 
Answer & Explanation Answer: D) 2048

Explanation:

Given 11 questions of type True or False

 

Then, Each of these questions can be answered in 2 ways (True or false)

 

Therefore, no. of ways of answering 11 questions = 211 = 2048 ways.

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Filed Under: Permutations and Combinations
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9 10094
Q:

A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27,  what is the total amount  ?

A) Rs. 159 B) Rs. 96
C) Rs. 147 D) Rs. 105
 
Answer & Explanation Answer: D) Rs. 105

Explanation:

K : L : M = 100 : 45 : 30
              = 20 : 9 : 6

Given L share is 27

=> 9  ------  27
      35 ------  ?

      => 105

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Filed Under: Ratios and Proportions
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11 10081
Q:

If 1/8 of a pencil is black, 1/2 of the remaining is white and the remaining, 3/2cm is blue. Find the total length of the pencil?

A) 8 cms B) 7 cms
C) 9 cms D) 11 cms
 
Answer & Explanation Answer: A) 8 cms

Explanation:

Let the total length of the pencil = x cms

From the given data,

'x/8' is black

Remaining part = x - x/8 = 7x/8

1/2 of 7x/8 is white

=> 7x/16 is white (Remaining part is 7x/16)

And given that the remaining part is blue and is 3 1/2 cm = 7/2 = 3.5 cm

That remaining part = 7x/16

Therefore,

7x/16 = 7/2

x = 16/2 = 8

Hence, the total length of the pencil = x = 8 cm.

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Filed Under: Percentage
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17 10078
Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

A) .I only B) III only
C) I or II D) II and Either I or III only
 
Answer & Explanation Answer: D) II and Either I or III only

Explanation:

   I. gives, Rate = 5% p.a.

 

 II. gives, S.I. for 1 year = Rs. 600.

 

III. gives, sum = 10 x (S.I. for 2 years).

 


 Now I, and II give the sum.


 For this sum, C.I. and hence amount can be obtained.


 Thus, III is redundant.


 Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.


 Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.


Thus,Rate =100*12002*12000 =5%


Thus, C.I. for 2 years and therefore, amount can be obtained.


Thus, I is redundant.



Hence, I or III redundan
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Filed Under: Compound Interest
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5 10072
Q:

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ?

A) 15 B) 20
C) 10 D) 8
 
Answer & Explanation Answer: C) 10

Explanation:

Let the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy

=>5(300/x) - 10x - 50 = 0 => -150+x2+5x

multiplying both sides by -1/10x

=> x2+15x-10x-150=0

=> x(x + 15) - 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.

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Filed Under: Simplification
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9 10060
Q:

On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?

A) 14 B) 16
C) 12 D) 15
 
Answer & Explanation Answer: D) 15

Explanation:

Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'

=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.

=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15

Therefore, 15 sweets were each student originally supposed to get.

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Filed Under: Average
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10 10059
Q:

A man goes down stream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the strean are 10km/hr and 14km/hr respectively, the distance of the destination from the string place is 

A) 16 km B) 18 km
C) 21 km D) 25 km
 
Answer & Explanation Answer: C) 21 km

Explanation:

Let the distance covered be D km. 

 D10+4+ D10-4 = 5

 D14+D6=5

 10D = 42 x 5 = 210

 

=> D = 21 km

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Filed Under: Boats and Streams
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32 10048
Q:

What is the ratio of 18 minutes to one hour ?

A) 1/5 B) 3/4
C) 1/7 D) 3/10
 
Answer & Explanation Answer: D) 3/10

Explanation:

One hour = 60 min

18/60 = 3/10

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Filed Under: Clocks
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39 10043