6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A) 22	B) 44
C) 66	D) 88

Answer & Explanation Answer: D) 88

Explanation:

We have: l = 20 ft and lb = 680 sq. ft.So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

3 9850

Q:

The certain worth of a certain sum due sometime hence is Rs. 1600 and the true discount is

Rs. 160. The banker's gain is:

A) 15	B) 16
C) 14	D) 13

Answer & Explanation Answer: B) 16

Explanation:

B.G. =(T.D.)^2/P.W.

= Rs. (160*160)/1600 = Rs. 16.

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Filed Under: Banker's Discount

1 9839

Q:

HCF of 1, 2, 3?

A) 3	B) 2
C) 1	D) 0

Answer & Explanation Answer: C) 1

Explanation:

Given numbers are 1, 2 and 3

Factors of 1 = 1

Factors of 2 = 1, 2

Factors of 3 = 1, 2 and 3

Common factors = 1

Hence, the HCF of 1, 2 and 3 = 1.

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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31 9832

Q:

A cuboid of dimension 24cm x 9cm x 8 cm is melted and smaller cubers are of side 3 cm is formed.find how many such cubes can be formed ?

A) 64	B) 56
C) 48	D) 40

Answer & Explanation Answer: A) 64

Explanation:

Volume of cuboid = (24 x 9 x 8) cm = 1728 cu.cm
Volume of small cube = (3 x 3 x 3) cm = 27 cu.cm

So, No. of small cubes formed = 1728/27 = 64.

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Filed Under: Volume and Surface Area
Exam Prep: CAT , Bank Exams , AIEEE
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5 9827

Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500	B) 400
C) 360	D) 480

Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18) m/s = 25 m/s

Time = 12 s

Distance/time = speed

=>3x/12 = 25 $\Rightarrow$ (25*12)/3

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y [where y is the length of the platform]

x =100m => 200+y = 45* 40/3
$\Rightarrow$ y = 400m

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Filed Under: Problems on Trains

13 9824

Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

A) 1 : 10	B) 10 : 1
C) 9 : 11	D) 11 : 9

Answer & Explanation Answer: A) 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk :: Water

6.4 0

$\frac{8}{1 + \frac{3}{8}} = \frac{64}{11}$

$\frac{64}{11}$ $\frac{64}{10} - \frac{64}{11}$

=> Milk : Water = 110 : 11 = 10 : 1

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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29 9822

Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90% $\inline \therefore$ saving = 10%

B's spending 75% $\therefore$ saving = 25%

C's spending 60% $\inline \therefore$ saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

$\inline \therefore$ 10% of A's saving = Rs.3

100% of A's saving = $\inline \frac{3}{10}\times 100$ = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving = $\inline \frac{5}{25}\times 100$ = Rs. 20

40% of C's saving = Rs.6

100% of C's saving = $\inline \frac{6}{40}\times 100$ = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share = $\inline \frac{30}{65}\times 6500$ = Rs. 3000

B's Share = $\inline \frac{20}{65}\times 6500$ = Rs. 2000

C's Share = $\inline \frac{15}{65}\times 6500$ = Rs. 1500

Workspace

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Subject: Ratios and Proportions
Job Role: Bank PO

66 9766

Q:

Sony is one-fifth the age of her mother 15 years ago and Sony’s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother’s ages is 31 then how old is Sony's mother ?

A) 40	B) 50
C) 60	D) 70

Answer & Explanation Answer: B) 50

Explanation:

Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.

Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24

Sum = 24 + 7 = 31.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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9 9717

Quantitative Aptitude - Arithmetic Ability Questions

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