Quantitative Aptitude - Arithmetic Ability Questions

Cost price of the article is given by

= 400x100/(20+20)

= Rs.1000

K's work in a day(1st day) = 1/30
L's work in a day(2nd day)= -1/60(demolishing)
hence in 2 days, combined work= 1/30 - 1/60 =1/60
since both works alternatively, K will work in odd days and L will work in even days.
1/60 unit work is done in 2 days
58/60 unit work will be done in 2 x 58 days = 116 days
Remaining work = 1-58/60 = 1/30
Next day, it will be K's turn and K will finish the remaining 1/30 work.
hence total days = 116 + 1 = 117.

Let the present ages of Arun and Harish be 4x and 3x years respectively.

Then, 4x + 6 = 26 => x = 5

Harish's age = 3x = 15 years.

Raj Tarun's age = 0 when he was born.
Then, given his brother is 6 years old.
Then his father is 6 + 32 = 38 when Raj Tarun was born
And his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was born
and his sister is 25 year younger than his mother
so Raj Tarun's sister was 10 years old when Raj Tarun was born.

Vol of silver = πR2h  = 66 C.C  

Given D= 1mm => R = D/2 = 1/20 cm  

=> 227×1202×h = 66

= 66 x 400 x (7/22) = 8400 cm = 84 mtrs.

A's spending 90%                 saving = 10%

B's spending 75%                 saving = 25%

C's spending 60%                 saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

 10% of A's saving = Rs.3

100% of A's saving =  = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving =  = Rs. 20

40% of C's saving = Rs.6

100% of C's saving =  = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share  =   = Rs. 3000

B's Share   =  = Rs. 2000

C's Share  =  = Rs. 1500

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 368/16 = 23
Number of cans of Pepsi = 80/16 = 5
Number of cans of Sprite = 144/16 = 9
The total number of cans required = 23 + 5 + 9 = 37 cans.

(45 x 9)/40 = (M x 7)/56 => M = 81

=> 81 – 45 = 36