6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ?

A) 45	B) 24
C) 42	D) 54

Answer & Explanation Answer: D) 54

Explanation:

By trial and error method from the given options,

as 54 - 45 = (1/11) x (45+54) = 99/11 = 9

Hence this satisfies the given conditions.

Then the woman's husband age is 54.

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Filed Under: Problems on Ages
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10 8211

Q:

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

A) 400 m	B) 300 m
C) 500 m	D) 600 m

Answer & Explanation Answer: A) 400 m

Explanation:

Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.

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Filed Under: Problems on Trains
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7 8210

Q:

A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum ?

A) Rs.8000	B) Rs.6500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: C) Rs.7500

Explanation:

$p = \frac{(d \times 100^{2})}{R^{2}}$

Where d is difference, r is rate of interest.

=> (48 x 100 x 100) / 8 x 8 = Rs.7500

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Filed Under: Simple Interest
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6 8201

Q:

Mr. Karthik drives to work at an average speed of 48 km/hr. Time taken to cover the first 60% of the distance is 20 minutes more than the time taken to cover the remaining distance. Then how far is his office ?

A) 40 km	B) 50 km
C) 70 km	D) 80 km

Answer & Explanation Answer: D) 80 km

Explanation:

Let the total distance be 'x' km.

Time taken to cover remaining 40% of x distance is $t 1 = \frac{40 \times x}{100 \times 48}$

But given time taken to cover first 60% of x distance is $t 2 = t 1 + \frac{20}{60} h r s$

$t 2 = \frac{60 \times x}{100 \times 48}$

$∴ \frac{60 \times x}{100 \times 48} = \frac{40 \times x}{100 \times 48} + \frac{20}{60}$

x=80 km.

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Filed Under: Time and Distance
Exam Prep: CAT
Job Role: Bank PO

12 8196

Q:

0.002 * 0.5 = ?

A) 0.0001	B) 0.001
C) 0.01	D) 0.1

Answer & Explanation Answer: B) 0.001

Explanation:

2 * 5 = 10. Sum of decimal places = 4.

.002 * .5 = 0.0010 = 0.001

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Filed Under: Decimal Fractions

16 8191

Q:

A five-year promissory note with a face value of $3500, bearing interest at 11% compounded semiannually, was sold 21 months after its issue date to yield the buyer 10% compounded quarterly.What amount was paid for the note

A) 4336.93	B) 5336
C) 6336	D) 7336

Answer & Explanation Answer: A) 4336.93

Explanation:

i=j/m

Maturity value = PV(1 + i)^n

Term = 5 years - 21 months= 3.25 years

Price paid = FV(1+ i )^-n

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Filed Under: Compound Interest
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7 8185

Q:

A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?

A) 1/5	B) 1/6
C) 1/7	D) 1/8

Answer & Explanation Answer: B) 1/6

Explanation:

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

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Filed Under: Time and Work
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7 8180

Q:

The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ?

A) 97	B) 98
C) 92	D) 93

Answer & Explanation Answer: A) 97

Explanation:

Marks in English = 85×7 – 83×6

= 595 – 498

= 97

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Filed Under: Average
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22 8172

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