Quantitative Aptitude - Arithmetic Ability Questions

Q:

Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh?

A) Rs. 5000 B) Rs. 6200
C) Rs. 8100 D) R. 7600
 
Answer & Explanation Answer: A) Rs. 5000

Explanation:

Let the amount invested by saketh = RS. p

Now, that of sandeep = 20,000 x 6

saketh = 12 x p

Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000)

=> 12000012p = 60003000 => p= Rs. 5000

Hence, the amount investe by saketh  = Rs. p  = Rs. 5000.

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Q:

1.123 + 11.23 + 112.3 = ?

 

A) 123.453 B) 124.653
C) 125.253 D) 123.953
 
Answer & Explanation Answer: B) 124.653

Explanation:
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Q:

Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ?

A) 5.75 kms B) 7.36 kms
C) 8.2 kms D) 6.98 kms
 
Answer & Explanation Answer: B) 7.36 kms

Explanation:

Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

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Q:

A town has a population of 4000 requires 140 liters of water per head. It has a tank measuring 18m x 12m x 8m. The water of this tank will suffice for ____ days?

A) 3 B) 4
C) 5 D) 2
 
Answer & Explanation Answer: A) 3

Explanation:

Water required = 4000 x 140 = 560000 lit = 560 cu.m (1 cu.m = 1000 lit)

Volume of tank = 18 x 12 x 8 = 1728 cu.m

Water of this tank will suffice for = 1728/560 = 3 days.

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Q:

What is the present worth of a bill of Rs.1764 due 2 years hence at 5% compound interest is

A) Rs. 1600 B) Rs. 1200
C) Rs. 1800 D) Rs. 1400
 
Answer & Explanation Answer: A) Rs. 1600

Explanation:

Since the compound interest is taken here,

 

 PW1+51002=1764

 

=> PW = 1600

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Q:

Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + ....

A) 30,400 B) 30,200
C) 34,600 D) 38,400
 
Answer & Explanation Answer: A) 30,400

Explanation:

we can treat every two consecutive terms as one.
So, we will have a total of 100 terms of the nature:
(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,....

 

We know the sum of n terms  nn+12

 

Now, a= 7, d=6 and n=100
Hence the sum of the given series is
S= 100/2 x[2 x 7 + 99 x 6]
=> 50[608]
=> 30,400.

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Q:

Vishal and Raghu jointly started a business. Vishal invested three times as Raghu did and invested his money for double time as compared to Raghu. Raghu earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was  ?

A) Rs. 28,000 B) Rs. 18,000
C) Rs. 14,000 D) Rs. 8,000
 
Answer & Explanation Answer: A) Rs. 28,000

Explanation:

Investments ratio is = 3:1
Time period ratio is = 2:1

As they are proportional to gain

------
Gain ratio of Vishal and raghu = 6:1

But given Raghu got Rs. 4000, 

=? 1 ----- 4000
     7 -----    ?

=> Rs.28,000

The total gain = Rs.28,000

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Q:

A and B started a business after investing Rs. 12,000 and Rs. 14,400 respectively. At the end of the year B gets 12% of the total profit as management fees and the rest amount is distributed between both the partners in the ratio of their investments. If total annual profit is Rs. 7,500, then find the difference between their profits.

A) Rs. 1250 B) Rs. 600
C) Rs. 900 D) Rs. 1500
 
Answer & Explanation Answer: D) Rs. 1500

Explanation:

From the given data,

Ratio of capital = 12000 : 14400 = 5 : 6

Required Difference = 

6 - 56 + 5 88100 x 7500 + 12100 x 7500= 111 x 88 x 75  + 12 x 75= 600 + 900= 1500

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