Quantitative Aptitude - Arithmetic Ability Questions

If there are total 100 candidates,
40 candidates are really capable and
60 candidates are incapable.
Of the candidates who are really capable = 80%
40*(80/100)=32 pass the test and
of the incapable= 30%
60*(30/100)=18 pass the test.
Total candidates who passed the test = 32+18 = 50
The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

Let distance between A & B = d km
Let speed in still water = x kmph
Let speed of current = y kmph

from the given data,
d/x = 2

From A) we get d
From B) we get d/x+y
From C) we get y

So, Any one pair of A and B, B and C or C and A is sufficient to give the answer i.e, the speed of upstream.

Let O's share = Rs. P

=> N's share = 75100 x P = 3P4

M's share = 54 x 3P4 = 15P16

$$\begin{gathered} 15P16 + 3P4 + P = 4300 \\ => P = 4300 x 1643 = 1600 \end{gathered}$$ 

Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

A+7B=112

it is clear that A = 14, then it becomes A>=B, but A is smallest angle) given
so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)

Given exp =134÷54-1252-3-212= 134÷54-1252-112

= 134÷54-1230-112 = 134÷54-2924

 = 134÷30-2924=78

Given, 52416312=168 ⇔52416168=312 

Now , 52.4160.0168=5241616.8=52416168×10 =312×10=3120

Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio.

Ratio of K and L is

16000×8x×4=52

x = Rs. 12,800.