Quantitative Aptitude - Arithmetic Ability Questions

Q:

At the university entrance exam, a candidate is admitted according to whether he has passed or failed the test. Of the candidates who are really capable, 80 % pass the test and of the incapable, 30 % pass the test. Given that 40 % of the candidates are really capable, then the proportion of the really capable students who can pass the test to the total students who can pass is about ?

A) 11/24 B) 1/5
C) 16/25 D) 6/5
 
Answer & Explanation Answer: C) 16/25

Explanation:

If there are total 100 candidates,
40 candidates are really capable and
60 candidates are incapable.
Of the candidates who are really capable = 80%
40*(80/100)=32 pass the test and
of the incapable= 30%
60*(30/100)=18 pass the test.
Total candidates who passed the test = 32+18 = 50
The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

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Filed Under: Ratios and Proportions
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5 6122
Q:

K and L start a business jointly. K invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit L claims 2/7th share. How much money is contributed by L?

A) Rs. 13,204 B) Rs. 14,521
C) Rs. 12,800 D) Rs. 15,000
 
Answer & Explanation Answer: C) Rs. 12,800

Explanation:

Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio.

Ratio of K and L is


16000×8x×4=52


x = Rs. 12,800.

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Filed Under: Partnership
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8 6114
Q:

If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to

A) 55/601 B) 601/55
C) 11/120 D) 120/11
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b . Then, a+b =55 and ab = 5 x 120 = 600.

 

Therefore, Required sum = 1a+1b=a+bab=55600=11120

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Filed Under: HCF and LCM

7 6113
Q:

The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ?

A) 42.2 mts B) 33.45 mts
C) 66.6 mts D) 58.78 mts
 
Answer & Explanation Answer: C) 66.6 mts

Explanation:

ht1488353450.jpg image

From above diagram
AC represents the hill and DE represents the tower

Given that AC = 100 m

angleXAD = angleADB = 30° (∵ AX || BD )
angleXAE = angleAEC = 60° (∵ AX || CE)

Let DE = h

Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE

tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1)

tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)
∵ BD = CE and Substitute the value of CE from equation 1
100/√3 = 100−h(√3) => h = 66.66 mts

The height of the tower = 66.66 mts.

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Filed Under: Height and Distance
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17 6104
Q:

A person lends Rs. 300 to A at 4% and Rs.540 to B at 6% for the same time. if the total amount that he gets at the end is Rs. 1032. What is the time?

Answer

Money lent to A+B = (300 + 540) = Rs. 840 


Amount received = Rs. 1032 


Interest received = Rs. 1032 - Rs.840 = Rs. 192


 


Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12 


 


Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36 


 


 


Total yearly interest = Rs.(12+36) = Rs.48 


If interest is Rs. 48, time = 1 year 


If interest is Rs. 192, time =  192/48 = 4 years 

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Subject: Simple Interest Exam Prep: GATE , CAT , Bank Exams , AIEEE
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14 6100
Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new student is?

Answer

Total age of 10 students = 150 years


Total age of 15 students = 240 years


Total age of 5 new students = 240 - 150 = 90 years


 Average age of 5 new students = 90/5 = 18 years.

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Subject: Problems on Ages

5 6095
Q:

A sum of Rs. 4,300 is distributed among M, N and O, such that M receives 25% more than N and N receives 25% less than O. What is O’s share in the amount?

A) 1564 B) 1600
C) 1632 D) 1714
 
Answer & Explanation Answer: B) 1600

Explanation:

Let O's share = Rs. P

=> N's share = 75100 x P = 3P4

M's share = 54 x 3P4 = 15P16

15P16 + 3P4 + P = 4300=> P = 4300 x 1643 = 1600 

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14 6094
Q:

12 days payment to the servant in a cloth showroom in festival season is Rs. 400 plus one shirt. The servant leaves after 9 days and recieves Rs. 280 and a shirt. What is the price of the shirt ? 

A) Rs. 80 B) Rs. 120
C) Rs. 70 D) Rs. 100
 
Answer & Explanation Answer: A) Rs. 80

Explanation:

The servant worked for 9 days instead of 12 days, he should receive 9/12 of his total payment

Let the price of 1 shirt be Rs. S 

i.e., 3/4 (400 + S).

However, the question states that the servant receive Rs. 280 + S where S is the price of the shirt.

By equating the two equations we get 3/4 (400 + S) = 280 + S.

Therefore, Price of the shirt S = Rs. 80.

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Filed Under: Profit and Loss
Exam Prep: Bank Exams , CAT , GATE
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22 6093