6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A tank is filled in eight hours by three pipes K, L and M. Pipe K is twice as fast as pipe L, and L is twice as fast as M. How much time will pipe L alone take to fill the tank ?

A) 32 hrs	B) 24 hrs
C) 28 hrs	D) 26 hrs

Answer & Explanation Answer: C) 28 hrs

Explanation:

1/K + 1/L + 1/M = 1/8 (Given)
Also given that K = 2L and L = 2M
=> 1/2L + 1/L + 2/L = 1/8
=> (1 + 2 + 4)/2L = 1/8
=> 2L/7 = 8
=> L = 28 hours.

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

8 6202

Q:

Application of Inverse Proportion

If 20 persons can do a piece of work in 7 days then calculate the number of persons require to complete the work in 28 days

Answer

Number of persons * days = work

20 * 7 = 140 man- days

Now, x * 28 = 140 men- days

=> x =5

Therefore in second case the required number of person is 5.

Second method:

Since work is constant, therefore M1 x D1= M2 x D2

20 x 7 = M2 x 28

=> M2 = 5

Workspace

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Subject: Time and Work

5 6189

Q:

A person lends Rs. 300 to A at 4% and Rs.540 to B at 6% for the same time. if the total amount that he gets at the end is Rs. 1032. What is the time?

Answer

Money lent to A+B = (300 + 540) = Rs. 840

Amount received = Rs. 1032

Interest received = Rs. 1032 - Rs.840 = Rs. 192

Interest on Rs. 300 lent to A for 1 year = $\frac{300 \times 1 \times 4}{100}$ = Rs. 12

Interest on Rs.540 lent to B for 1 year = $\frac{540 \times 6 \times 1}{100}$ = Rs. 36

Total yearly interest = Rs.(12+36) = Rs.48

If interest is Rs. 48, time = 1 year

If interest is Rs. 192, time = 192/48 = 4 years

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Subject: Simple Interest Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

14 6170

Q:

The capacity of a tank is 2400 $m^{3}$ . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 $m^{3}$ /minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.

A) 46 cub.m/min	B) 44 cub.m/min
C) 48 cub.m/min	D) 50 cub.m/min

Answer & Explanation Answer: D) 50 cub.m/min

Explanation:

Let filling capacity of the pump be 'F' $m^{3} / \min$

Then, the filling capacity of the pump will be (F + 10) $m^{3} / \min$

From the given data,

$\frac{2400}{F} - \frac{2400}{F + 10} = 8 \Rightarrow 2400 [\frac{F + 10 - F}{F (F + 10)}] = 8 \Rightarrow F^{2} + 10 F - 3000 = 0 \Rightarrow F = 50 m^{3} / \min$

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

15 6167

Q:

5 sin(x)+ 12 cos(x) + r is always greater than or equal to zero. What is the smallest value satisfied by 'r' ?

A) -13	B) 11
C) 13	D) -11

Answer & Explanation Answer: C) 13

Explanation:

Given,

5sinx + 12cosx ≥ -r

$\Rightarrow 13 (\frac{5}{13} \sin x + \frac{12}{13} \cos x) \geq - r$ cosx) ≥ -r

$\frac{5}{13}$ = cosA => sinA = $\frac{12}{13}$

=> 13(sinx cosA + sinA cosx) ≥ -r

=> 13(sin(x + A)) ≥ -r

we know that , -1 ≤ sin (angle) ≤ 1

=> 13sin (x + A) ≥ -13 $\Rightarrow r_{m i n} = 13$

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Filed Under: Simplification
Exam Prep: CAT
Job Role: Bank PO

8 6157

Q:

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A) 16cm	B) 18cm
C) 24cm	D) .Data inadequate

Answer & Explanation Answer: B) 18cm

Explanation:

2(l+b)/b = 5/1

=> 2l + 2b = 5b

=> 3b = 2l

=> b =(2/3) x l

Then, Area = 216 sq.cm

l x b = 216

=> l x [(2/3)x l] =216

=> l x l = 324

=> l = 18 cm.

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Filed Under: Volume and Surface Area

0 6149

Q:

Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

A) 2	B) 7/8
C) 5/8	D) 1/2

Answer & Explanation Answer: D) 1/2

Explanation:

S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }

=> n(S) = 8

E = { HHH, HHT, HTH, THH }

=> n(E) = 4

P(E) = 4/8 = 1/2

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Filed Under: Probability

4 6141

Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000	B) Rs.4500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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9 6141

Quantitative Aptitude - Arithmetic Ability Questions

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