6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

5 sin(x)+ 12 cos(x) + r is always greater than or equal to zero. What is the smallest value satisfied by 'r' ?

A) -13	B) 11
C) 13	D) -11

Answer & Explanation Answer: C) 13

Explanation:

Given,

5sinx + 12cosx ≥ -r

$\Rightarrow 13 (\frac{5}{13} \sin x + \frac{12}{13} \cos x) \geq - r$ cosx) ≥ -r

$\frac{5}{13}$ = cosA => sinA = $\frac{12}{13}$

=> 13(sinx cosA + sinA cosx) ≥ -r

=> 13(sin(x + A)) ≥ -r

we know that , -1 ≤ sin (angle) ≤ 1

=> 13sin (x + A) ≥ -13 $\Rightarrow r_{m i n} = 13$

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Filed Under: Simplification
Exam Prep: CAT
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8 6395

Q:

The incomes of two persons A and B are in the ratio 3:4. If each saves Rs.100 per month, the ratio of their expenditures is 1:2. Find their incomes ?

A) 200, 400	B) 100, 300
C) 100, 200	D) 150, 200

Answer & Explanation Answer: D) 150, 200

Explanation:

The incomes of A and B be 3P and 4P.

Expenditures = Income - Savings

(3P - 100) and (4P - 100)

The ratio of their expenditure = 1:2

(3P - 100):(4P - 100) = 1:2

2P = 100 => P = 50

Their incomes = 150, 200

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Filed Under: Ratios and Proportions
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6 6392

Q:

The capacity of a tank is 2400 $m^{3}$ . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 $m^{3}$ /minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.

A) 46 cub.m/min	B) 44 cub.m/min
C) 48 cub.m/min	D) 50 cub.m/min

Answer & Explanation Answer: D) 50 cub.m/min

Explanation:

Let filling capacity of the pump be 'F' $m^{3} / \min$

Then, the filling capacity of the pump will be (F + 10) $m^{3} / \min$

From the given data,

$\frac{2400}{F} - \frac{2400}{F + 10} = 8 \Rightarrow 2400 [\frac{F + 10 - F}{F (F + 10)}] = 8 \Rightarrow F^{2} + 10 F - 3000 = 0 \Rightarrow F = 50 m^{3} / \min$

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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15 6372

Q:

12 days payment to the servant in a cloth showroom in festival season is Rs. 400 plus one shirt. The servant leaves after 9 days and recieves Rs. 280 and a shirt. What is the price of the shirt ?

A) Rs. 80	B) Rs. 120
C) Rs. 70	D) Rs. 100

Answer & Explanation Answer: A) Rs. 80

Explanation:

The servant worked for 9 days instead of 12 days, he should receive 9/12 of his total payment

Let the price of 1 shirt be Rs. S

i.e., 3/4 (400 + S).

However, the question states that the servant receive Rs. 280 + S where S is the price of the shirt.

By equating the two equations we get 3/4 (400 + S) = 280 + S.

Therefore, Price of the shirt S = Rs. 80.

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Filed Under: Profit and Loss
Exam Prep: Bank Exams , CAT , GATE
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22 6371

Q:

The true discount on a certain sum of money due 3 year hence is Rs.100 and the S.I. on the same sum for the same time and at the same rate is Rs.120. Find the sum and the rate percent.

A) (6 + 2/3)%	B) (5+ 2/3)%
C) (2+ 2/3)%	D) (4+ 2/3)%

Answer & Explanation Answer: A) (6 + 2/3)%

Explanation:

Sum ⇒ Amount

A = (SI x TD)/(SI - TD)

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Filed Under: True Discount
Exam Prep: Bank Exams
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3 6371

Q:

Priya can do a work in 16 days. In how many days will the work be completed by Sai, if the efficiency of Sai is 60% more than that of Priya ?

A) 8 days	B) 12 days
C) 14 days	D) 10 days

Answer & Explanation Answer: D) 10 days

Explanation:

Ratio of efficiencies of Priya and Sai is

Sai : Priya = 160 : 100 = 8 : 5

Given Priya completes the work in 16 days

Let number of days Sai completes the work be 'd'

=> 5×16 = 8×d

d = 10 days.

Therefore, number of days Sai completes the work is 10 days.

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Filed Under: Time and Work
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13 6362

Q:

Simplyfiy : $[3 \frac{1}{4} \div \{1 \frac{1}{4} - \frac{1}{2} (2 \frac{1}{2} - (\frac{1}{4} + \frac{1}{6}))\}]$

A) 78	B) 88
C) 98	D) 108

Answer & Explanation Answer: A) 78

Explanation:

Given exp = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{5}{2} - \frac{3 - 2}{12})\}]$ = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{5}{2} - \frac{1}{12})\}]$

= $[\frac{13}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{30 - 1}{12})\}]$ = $[\frac{13}{4} \div \{\frac{5}{4} - \frac{29}{24}\}]$

= $[\frac{13}{4} \div \frac{30 - 29}{24}]$ =78

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Filed Under: Simplification

4 6360

Q:

In an old Palace there are 50 stairs to go on top floor. Each is 20 cm high, 30 cm wide and 60 cm long. If all the stairs are re-plastered at the rate of Rs. 4 per 100 sq.cm. What is the expenditure ?

A) Rs. 4680	B) Rs. 7600
C) Rs. 6000	D) Rs. 5480

Answer & Explanation Answer: C) Rs. 6000

Explanation:

Total are of all stairs = 50 (20x60 + 30x60)

= 50 (1200 + 1800)

= 50 x 3000

= 150000 sq cm.

Given rate of 100 sq cm = Rs. 4

Then for 150000 sq. cm = ?

=> 4 x 150000/100 = Rs. 6000

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Filed Under: Area
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11 6356

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