Quantitative Aptitude - Arithmetic Ability Questions

1 to 300 = 300 numbers
squares btwn 1 to 300 = 1,4,9,16,25,36,49.....289 i.e, total 17
cubes = 1,8,27,64,125,216 i.e, 5
now 1 and 64 are common so total numbers that should be removed ( 17+5-2= 20 )
total 20 term removed so 300th term would be 320

Let Principal = Rs. P and Rate = R% p.a. Then,

Amount= Rs.P1+R1004

 C.I = P1+R1004-1

 P1+R1004-1=1491

Clearly, it does not give the answer

Given numbers are 585 546 514 404 206 369
Then interchanging the 1st and 3rd digits of the given numbers, we get
585 645 415 404 602 963
Now, arranging them in ascending order
963 645 602 585 415 404
Then the last second number is 415.

S = { (1, 1), (1, 2), (1, 3), (1, 4),(1, 5), (1, 6), (2, 1), (2, 2),.........(6, 5), (6, 6) }

=> n(S) = 6 x 6 = 36

E = {(6, 3), (5, 4), (4, 5), (3, 6) }

=> n(E) = 4

Therefore, P(E) = 4/36 = 1/9

0.46 = 46/100 = 23/50.

Sum of the numerator and denominator is 23 + 50 = 73

Given Pranay's profit in the share is Rs. 8750

But given that their investments are in the ratio 2:4:7

713×P = 8750

P = 16250

Now Anand's share = 413×16250 = Rs.5000

Thus both staements a and b are sufficient to answer this question.

Ratio of efficiencies of Priya and Sai is

Sai : Priya = 160 : 100 = 8 : 5

Given Priya completes the work in 16 days

Let number of days Sai completes the work be 'd'

=> 5×16 = 8×d

d = 10 days.

Therefore, number of days Sai completes the work is 10 days.