Quantitative Aptitude - Arithmetic Ability Questions

Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days.

Let the initial speed be '1'

Hence, Time = 22(24hrs - 2)

Noe new speed = 2/3

Let the number of days he take be 'D'

Therefore, 2224-2x3200=D24-2x2250

D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.

T.D. =Ö(P.W.*B.G)

B.G. =(T.D.)2/ P.W.      

       = Rs.[(110x110)/ 1100]

       = Rs. 11.

B.D.= (T.D. + B.G.) = Rs. (110 + 11) = Rs. 121.

We are not given a value of P in this problem, so either pick a value

for P and stick with that throughout the problem, or just let P = P.

We have that t = 1, and r = .055. To find the effective rate of interest,

first find out how much money we have after one year:

A = Pert

A = Pe(.055)(1)

A = 1.056541P.

Therefore, after 1 year, whatever the principal was, we now have 1.056541P.

Next, find out how much interest was earned, I, by subtracting the initial amount of money from the final amount:

I = A − P

  = 1.056541P − P

  = .056541P.

Finally, to find the effective rate of interest, use the simple interest formula, I = Prt. So,

I = Pr(1) = .056541P

.056541 = r.

Therefore, the effective rate of interest is 5.65%

Here among the given numbers, 3, 19, 67 are prime numbers. And 133 is not a prime number.

Hence, the odd number of the given numbers is 133.

T = 4 years

R = 5%

Banker's Gain, BG = Rs.200

TD= BG×100TR=200×1004×5=Rs.1000

 TD=PW×BG

⇒1000=PW×200

=>PW = Rs.5000

?2 = 325 – 144 + 75 + 68
= 468 – 144 = 324
(?) = 18,-18

$$\begin{gathered} 75x321415 ÷ 525100 \\ 94 ÷ 525100 \\ 9002100 \\ = 37 \end{gathered}$$