6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain?

A) 400	B) 376
C) 382	D) 356

Answer & Explanation Answer: A) 400

Explanation:

1st day the girl read = 40%

2nd day she read = 34 %

Remaining percentage of book = 100% - (40% +34%) = 26%

But given last two days she read equal number of pages

=> Each day she read 26%/2 = 13%

Last day she read 52 pages = 13%

13% = 52

1% = 4

=> 100% = 400

Total pages in the book is 400.

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12 5896

Q:

A six-digit number is formed by repeating a three-digit number; for example, 404404 or 415415 etc. Any number of this form is always exactly divisible by

A) 101	B) 901
C) 1001	D) 789

Answer & Explanation Answer: C) 1001

Explanation:

Here by trial and error method, we can obseve that

404404 = 404 x 1001; 415415 = 415 x 1001, etc.

So, any number of this form is divisible by 1001.

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7 5892

Q:

The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ?

Question :

What is the height of a right-angled triangle ?

Statements :

A. The area of the triangle is 20 times its base.

B. The perimeter of the triangle is equal to that of a square of the side 10 cm.

A) Only statement A is required	B) Only statement B is required
C) Both A & B are required	D) Neither (A) nor (B) is reuired

Answer & Explanation Answer: A) Only statement A is required

Explanation:

From statement (A),

20b = (1/2) × b × h

h = 40 cm.

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Filed Under: Area
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27 5890

Q:

How much money would you need to deposit today at 9% annual interest compounded monthly to have $12000 in the account after 6 years?

A) 9007	B) 4007
C) 7007.08	D) 8oo7

Answer & Explanation Answer: C) 7007.08

Explanation:

FV=P(1+r/n)^nt

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0 5888

Q:

Find the compound interest on Rs.16,000 at 20% per annum for 9 months, compounded quartely.

A) Rs.2522	B) Rs.2422
C) Rs.3522	D) Rs.2322

Answer & Explanation Answer: A) Rs.2522

Explanation:

Principal = Rs.16,000;

Time=9 months = 3 quarters;

Amount

=Rs.[16000x(1+5/100)³] =[16000x21/20x21/20x21/20]

= Rs.18522.

C.I

= Rs.(18522 - 16000)

= Rs.2522.

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0 5882

Q:

Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.

A) 25 sq.cm	B) 16 sq.cm
C) 9 sq.cm	D) 4 sq.cm

Answer & Explanation Answer: A) 25 sq.cm

Explanation:

Given length of the rectangle = 3 cm

Breadth of the rectangle = 4 cm

Then, the diagonal of the rectangle $D = \sqrt{3^{2} + 4^{2}} = \sqrt{25} = 5$

Then, it implies side of square = 5 cm

We know that Area of square = S x S = 5 x 5 = 25 sq.cm.

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18 5876

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9	B) 605/9
C) 645/9	D) 700/9

Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

$\frac{1.8 x}{100} = 1.4$

x = $\frac{1.4 \times 100}{1.8} = \frac{700}{9} = 77 \frac{7}{9}$ .

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8 5873

Q:

If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ?

A) 56	B) 64
C) 87	D) 78

Answer & Explanation Answer: D) 78

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

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Filed Under: Average
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27 5871

Quantitative Aptitude - Arithmetic Ability Questions

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