Quantitative Aptitude - Arithmetic Ability Questions

From the given data,

When the price of rice is decreased by 10%, the value of Rs. 270 would become

270 x 100/90 = 300

Now, the value 270 becomes 300

And given, the girl could buy 1 kg extra for that value

Change in value = 300 - 270 = Rs. 30

Therefore, 1 kg extra rice she can get for Rs. 30

=> The original price of rice = Rs. 30/kg.

As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.  

Let M litres milk be added

=> 60 + M40 = 31

=> 60 + M = 120

=> M = 60 lit.

Let the sum be Rs. x. Then

C.I=x[1+4/100)^2-x]=[626/675x-x]

S.I=x^2/25

C.I-S.I=1

Let no. of boys be 'B' and no. of girls be 'G'

Here from given data,

B + G = 1650 .....(1)

B - G = 400 .....(2)

From (1) & (2), we get

2B = 2050

=> B = 1025

=> G = 1650 - 1025 = 625

Hence, the % of girls = 625 x 100/1650

=> 38% (approx).

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

Let the sum(principal) received by A and B are x and y.

(1+r) =  =

Then,  =

Hence, the ratio in which the sum is divided =121:100

1523+2323=19-423+19+423  

 The remainder on dividing by 19 will be -423+423= 0.