6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A town has a population of 4000 requires 140 liters of water per head. It has a tank measuring 18m x 12m x 8m. The water of this tank will suffice for ____ days?

A) 3	B) 4
C) 5	D) 2

Answer & Explanation Answer: A) 3

Explanation:

Water required = 4000 x 140 = 560000 lit = 560 cu.m (1 cu.m = 1000 lit)

Volume of tank = 18 x 12 x 8 = 1728 cu.m

Water of this tank will suffice for = 1728/560 = 3 days.

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Filed Under: Volume and Surface Area
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35 5727

Q:

$[\sqrt[3]{250047} + (56)^{2}] \div 7 = ?$

A) 547	B) 475
C) 455	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
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9 5725

Q:

If $A = \frac{l o g_{3} (2187)}{5}$ and $B = l o g_{243} (2187)$ , then which one of the following is correct?

A) A	B) A=B
C) A>B	D) can't be determined

Answer & Explanation Answer: B) A=B

Explanation:

Given $A = \frac{\log_{3} (2187)}{5} a n d B = \log_{243} (2187)$

$B = \log_{3^{5}} (2187) = \frac{\log_{3} (2187)}{5}$

=> A

Therefore, A = B

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Filed Under: Logarithms
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7 5719

Q:

Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh?

A) Rs. 5000	B) Rs. 6200
C) Rs. 8100	D) R. 7600

Answer & Explanation Answer: A) Rs. 5000

Explanation:

Let the amount invested by saketh = RS. p

Now, that of sandeep = 20,000 x 6

saketh = 12 x p

Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000)

=> $\frac{120000}{12 p} = \frac{6000}{3000} = > p = Rs . 5000$

Hence, the amount investe by saketh = Rs. p = Rs. 5000.

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Filed Under: Partnership
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13 5719

Q:

Find value of $\frac{\log \sqrt{27} + \log 8 + l o g \sqrt{1000}}{\log 120}$

A) 1/2	B) 3/2
C) 2	D) 2/3

Answer & Explanation Answer: B) 3/2

Explanation:

$= \frac{\log \sqrt{3^{3}} + \log 2^{3} + \log \sqrt{10^{3}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\log (3^{3})^{\frac{1}{2}} + \log 2^{3} + \log {(10^{3})}^{\frac{1}{2}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\frac{1}{2} \log 3^{3} + 3 \log 2 + \frac{1}{2} \log 10^{3}}{\log 10 + \log 3 + \log 2^{2}}$

$= \frac{\frac{3}{2} (\log 3 + 2 \log 2 + \log 10)}{\log 3 + 2 \log 2 + \log 10}$ = $\frac{3}{2}$

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Filed Under: Logarithms
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27 5717

Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

A) 14.5 lit	B) 12.8 lit
C) 11.6 lit	D) 10.46 lit

Answer & Explanation Answer: B) 12.8 lit

Explanation:

This can be solved as

$20 {(1 - \frac{4}{20})}^{2} = 20 {(1 - \frac{1}{5})}^{2} = 20 {(\frac{4}{5})}^{2} = 20 (\frac{16}{25}) = \frac{64}{5} = 12.8$

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Filed Under: Percentage
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11 5717

Q:

Two equal sums were lent, one at the rate of 11% per annum for five years and the other at the rate of 8% per annum for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum?

A) Rs. 14,400	B) Rs. 15,600
C) Rs. 14,850	D) Rs. 15,220

Answer & Explanation Answer: A) Rs. 14,400

Explanation:

Let the required Sum = Rs.S

From the given data,

1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

=> S = Rs. 14,400.

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Filed Under: Simple Interest
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18 5712

Q:

A school committee of 5 is to be formed from 12 students.How many committees can be formed if John must be on the committee?

A) 11P4	B) 11C4
C) 11P5	D) 11C5

Answer & Explanation Answer: B) 11C4

Explanation:

If John must be on the committee,we have 11 students remaining,out of which we choose 4. So, $11 C_{4}$

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Filed Under: Permutations and Combinations

0 5703

Quantitative Aptitude - Arithmetic Ability Questions

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