Quantitative Aptitude - Arithmetic Ability Questions

Let the numbers be x and (100-x).

Then,x100-x=5*495

 =>  x2-100x+2475=0

 =>  (x-55) (x-45) = 0

 =>  x = 55 or x = 45

  The numbers are 45 and 55

Required difference = (55-45) = 10

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005.

So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

3, 7, 6, 5, 9, 3, 12, 1, 15, ... has two different series

1) 3, 6, 9, 12, 15.....

2) 7, 5, 3, 1, .....

-1 is the next number.

41% of 600 - 250 = ? - 77% of 900

⇒ 246 - 250 = ? - 693

⇒ 246 -250 + 693 = ?

⇒ ? = 689

The given number series 100, 101, 97, 105, 90

100

100 + 1^2 = 101

101 - 2^2 = 97

97 + 3^2 = 106 ( not 105)

106 - 4^2 = 90

Hence, the odd man in the given series is 105.

The series follows the following pattern.

4

16 = 42

37 = 12+62

58 = 32+72

81 ≠52+82.

Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.