Quantitative Aptitude - Arithmetic Ability Questions

Total balls = 40

Red balls = 18

Let green balls are x

Then, (18/40) × (

Given a jeep travels a certain distance taking 6 hrs in forward journey
During the return journey, it takes 4 hrs with an increased speed 12 km/hr
Let 'x' be the distance.
Now, speed is given by distance/time.
Here the difference between both speeds = 12

 x4 - x6 = 12

 3x - 2x12 = 12

=> x = 144 km

Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.

Let the present age's of mother be 'M' and that of her son be 'S'.

According to the given data in the question,

M - 5 = 3(S - 5)

F - 3S = -10  ...............(1)

Then given ,

M + 5 : S + 5 = 11 : 5 

=> 5M - 11S = 30 ..............(2)

From (1) & (2), we get

S = 20

Then by substituting S = 20 in (1) or (2), we get

M = 50.

Hence, the present age of mother is M = 50 years.

Let the initial speed of Akhil be '4p' kmph

Then speed after decrease in speed = '3p' kmph

We know that, 

Change in speed == Change in time

According to the given data,

$$\begin{gathered} 243p - 244p = 35 - 2560 \\ => p = 12 \end{gathered}$$

Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.

Let the age of the youngest child is 'X' years.
Then the child elder than the yongest is 'X + 3' yrs
Since each have 3yrs difference upto 5 children
And given that
=> X + X+3 + X+6 + X+9 + X+12 = 50
=> 5X + 30 = 50
=> X = 4 yrs.

sum = [(S.I x T.D)/(S.I-T.D)] = Rs. [(375 x 250)/(375-250)] = Rs.750 

Rate = (100 x 375)/(750 x 3) =1623 %

$$\begin{gathered} log3437 \\ log737 \\ 13log77 \\ We know that logxx = 1 \\ => 13 \end{gathered}$$

10% profit at half plot = 600000/2 x 10/100 = Rs. 30,000

15% profit at remaining half plot = 600000/2 x 15/100 = Rs. 45,000

Now, total profit = 30000 + 45000 = 75000

Profit % = 75000/600000 x 100 = 12.5 %