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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

At the beginning of March, Ryan had $621 in his savings bank account. On 10 March he deposited $60. If the bank pays 8% p.a. interest paid monthly and calculated on the minimum monthly balance, calculate the interest Ryan earns in March.

A) 2.14 B) 3.14
C) 5.14 D) 4.14
 
Answer & Explanation Answer: D) 4.14

Explanation:

I = (P x T x R) /100

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Filed Under: Simple Interest
Exam Prep: Bank Exams
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2 4914
Q:

A sum was invested for 3 years at simple interest at a certain rate. Had it been invested at 4% higher rate of interest, it would have fetched Rs 600 more. The sum is

A) Rs 4000 B) Rs 4950
C) Rs 5000 D) Rs 5150
 
Answer & Explanation Answer: C) Rs 5000

Explanation:

Let the rate of interest be R

(Interest at rate (R+4)%)–(Interest at R%)

= 600(PT(R+4)/100) –(PTR/100)

= 6003PR +12P –3PR = 60000

12P = 60000

P = 5000

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Filed Under: Simple Interest

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Q:

3 + 653-212-30+50 = ?

A) 3 B) 3sqrt{2}
C) 6 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:
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Filed Under: Square Roots and Cube Roots
Exam Prep: AIEEE , Bank Exams , CAT
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22 4905
Q:

Watson bought a book for Rs. 240 and sold to Johny at a profit  of 50%. Johny wants to sell this book to Shekar so that he earns a profit of 25%. But Shekar is adamant at buying this book at a discount of 10%. What marked price should Johny quote to Shekar so as to achieve desired profit ?

A) Rs. 450 B) Rs. 360
C) Rs. 415 D) Rs. 500
 
Answer & Explanation Answer: D) Rs. 500

Explanation:

Watson bought the book for Rs. 240 and sold to Johny at a profit of 50%.

S.P = C.P(1 + P%/100)

=> S.P for Watson = C.P for Johny = 240(1 + 50/100) = 240 x 1.5 = Rs. 360

Let Johny quoted the marked price of the book as Rs. M

We know, SP = M.P(1 - Discount(%)/100)

Here discount = 10% to Shekar,

S.P for Johny = M(1 - 10/100) = 0.9M

But Johny want to earn 25% profit,

=> S.P = C.P(1 + P%/100)

=> 0.9M = 360(1 + 25/100)

=> M = (360x1.25)/0.9

=> M = Rs. 500

Therefore, Johny should quote Rs. 500 as the marked price of the book to get 25% profit and allowing 10% discount to Shekar.

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Filed Under: Profit and Loss
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7 4893
Q:

A Woman’s downstream swimming rate is thrice of her upstream swimming rate. If she covers 12 km upstream in 2.5 hours, what distance she will cover in 5 hours downstream?

 

A) 72 km B) 36 km
C) 56 km D) 42 km
 
Answer & Explanation Answer: A) 72 km

Explanation:

Rate of her upstream = 12/2.5 = 4.8 km/hr

Then, ATQ

Rate of downstream = 4.8 x 3 = 14.4 km/hr

 

Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

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Filed Under: Boats and Streams
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17 4893
Q:

If A had worked alone he would have taken 63 hours to do the task. What is B's share, if A and B work together on a task finishing it in 36 hours and they get paid Rs 5,950 for it?

A) 3400 B) 3600
C) 2550 D) 2750
 
Answer & Explanation Answer: C) 2550

Explanation:
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Filed Under: Time and Work
Exam Prep: Bank Exams

4 4881
Q:

A,B,C,D,E,F,G and H are sitting around a circular table facing the centre but not necessarily in the same order. G sits third to the right of C. E is second to the right of G and 4th to the right of H. B is fourth to the right of C. D is not an immediate neighbour of E. A and C are immediate neighbours.

 Which of the following is/are correct ?

A) F is third to the left of B B) F is second to the right of B
C) B is an immediate neighbour of D D) All of the above
 
Answer & Explanation Answer: B) F is second to the right of B

Explanation:

From the given information, the circular arrangement is

EXP.

Here F is second to the right of B and the remaning all are wrong.

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Filed Under: Permutations and Combinations
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6 4881
Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?

A) 6/19 B) 3/10
C) 7/10 D) 6/17
 
Answer & Explanation Answer: B) 3/10

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

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Filed Under: Probability
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