Quantitative Aptitude - Arithmetic Ability Questions

Q:

How many times in a day, are the hands of a clock in straight line but opposite in direction?

A) 11 B) 22
C) 33 D) 44
 
Answer & Explanation Answer: B) 22

Explanation:

The hands of a clock point in opposite directions (in the same straight line) 11 times in every
12 hours. (Because between 5 and 7 they point in opposite directions at 6 o'clcok only).
So, in a day, the hands point in the opposite directions 22 times

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

8 5020
Q:

A Woman’s downstream swimming rate is thrice of her upstream swimming rate. If she covers 12 km upstream in 2.5 hours, what distance she will cover in 5 hours downstream?

 

A) 72 km B) 36 km
C) 56 km D) 42 km
 
Answer & Explanation Answer: A) 72 km

Explanation:

Rate of her upstream = 12/2.5 = 4.8 km/hr

Then, ATQ

Rate of downstream = 4.8 x 3 = 14.4 km/hr

 

Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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17 5017
Q:

Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?

A) 31 years B) 37 years
C) 46 years D) 29 years
 
Answer & Explanation Answer: A) 31 years

Explanation:

Let the present age of Pinky be x years

 

Then the age of Mary is x - 12 years

 

After 3 years,

 

Ratio of  MaryPinky = x - 9x + 3 = 58

 

8x - 72 = 5x +15

 

=> 3x = 87

 

=> x = 29

 

=> Age of Pinky = 29 years

 

=> Age of Mary = 29 - 12 = 17 years

 

Present age of Sam = 29 + 17 = 46

 

Before 15 years Sam age = 46 - 15 = 31 years.

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Filed Under: Problems on Ages
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9 5013
Q:

A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?

A) 1260 B) 210
C) 210 x 6! D) 1512
 
Answer & Explanation Answer: A) 1260

Explanation:

A team of 6 members has to be selected from the 10 players. This can be done in 10C6 or 210 ways.

Now, the captain can be selected from these 6 players in 6 ways.
Therefore, total ways the selection can be made is 210×6= 1260

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0 5012
Q:

If watches bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 425. What is the greatest possible profit that might be made in selling nine watches ?

A) Rs. 1800 B) Rs. 2000
C) Rs. 2025 D) Rs. 1750
 
Answer & Explanation Answer: C) Rs. 2025

Explanation:

Profit would be maximum if watches are brought for Rs. 200 and sold for Rs. 425
Profit = Rs. (425 - 200) = Rs. 225
Profit of 9 watches = Rs. 225 x 9 = Rs.2,025.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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5 5010
Q:

If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time

A) Rs.51.25 B) Rs.61.25
C) Rs.51 D) Rs.42
 
Answer & Explanation Answer: A) Rs.51.25

Explanation:

Sum = Rs.(50*100)/2*5=Rs.500

Amount=Rs.[500*(1+5/100)2]

= Rs. 551.25

 

 C.I = Rs.(551.25-500)= Rs.51.25

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 4994
Q:

 0.204×420.07×3.4 is equal to:

A) 1/6 B) 0.06
C) 0.6 D) 6
 
Answer & Explanation Answer: D) 6

Explanation:

0.204×420.07×3.4=8568238=36 =6

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7 4987
Q:

If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 

A) 9! B) 9!/2
C) 10! D) 10!/2
 
Answer & Explanation Answer: D) 10!/2

Explanation:

As A1 speaks always after A2, they can speak only in  1st  to 9th places and 

 

A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place 

 

A2 can speak in 9 places the remaining 

 

 A3, A4, A5,...A10  has no restriction. So, they can speak in 9.8! ways. i.e

 

when A2 speaks in the first place, the number of ways they can speak is 9.8!.

 

When A2 speaks in second place, the number of ways they can speak is  8.8!.

 

When A2 speaks in third place, the number of ways they can speak is  7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8!

 

 

 

Therefore,Total Number of ways they can  speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2

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Filed Under: Permutations and Combinations
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5 4977