Quantitative Aptitude - Arithmetic Ability Questions

Q:

Train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 20 seconds. The length of train K is three-fourths the length of train L. What is the ratio of the speed of train K to that of train L   ?

A) 1 : 3 B) 2 : 1
C) 3 : 1 D) 1 : 2
 
Answer & Explanation Answer: B) 2 : 1

Explanation:

Given that train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 15 seconds.

Let the length of train K be Lk and that of train L be Ll

given that Lk = 3/4 Ll

As the train K and L crosses the pole in 30 seconds and 80 seconds respectively,
=> Speed of train K = sk = Lk/30

Speed of train L = sl = Ll/80

Lk = 3/4 Ll
=> sk = 3/4 Ll/(30) = Ll/40

Ratio of their speeds = sk : sl
= Ll/40 : Ll/80

=> 1/40 : 1/80  =  2 : 1

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Filed Under: Problems on Trains
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7 4848
Q:

The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than a side of the square and its breadth is 3 cm less than the side of the square. What is the perimeter of the rectangle ? 

A) 15 cm B) 18 cm
C) 34 cm D) 26 cm
 
Answer & Explanation Answer: C) 34 cm

Explanation:

Let the side of the square be 's' cm

 

length of rectangle = (s+5) cm

 

breadth of rectangle = (s-3)cm

 

(s+5) (s-3) = 

 

s2 - 5s - 3s - 15 = s2 

 

2s = 15

 

Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2)

 

= 2(15 + 2) = 34 cm 

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Filed Under: Area
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28 4848
Q:

On the occasion of New Year, each student of a class sends greeting cards to the others. If there are 21 students in the class, what is the total number of greeting cards exchanged by the students?

A) 380 B) 420
C) 441 D) 400
 
Answer & Explanation Answer: B) 420

Explanation:

Given total number of students in the class = 21

 

So each student will have 20 greeting cards to be send or receive (21 - 1(himself))

 

Therefore, the total number of greeting cards exchanged by the students = 20 x 21 = 420.

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Q:

In an examination, a student scores 4 marks for every correct answer and loses I mark for every wrong answer. If he attempts in all 60 questions and secures 130 marks, the number of questions he attempts correctly, is:

A) 35 B) 38
C) 40 D) 42
 
Answer & Explanation Answer: B) 38

Explanation:

Let the number of correct answers be X.

Number of incorrect answers = (60 – X).

Therefore, 4x – (60 – x) = 130 

=> 5x = 190  => x = 38

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Filed Under: Simplification

2 4839
Q:

The tax on an article decreases by 10% and its consumption increases by 10%. Find the effect percent on its revenue?

Answer

-10+10-10*10100  % = -1%


 


\inline \therefore Decrease in revenue = 1%

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Subject: Percentage Exam Prep: Bank Exams

13 4839
Q:

Cube root of 729 then square it

A) 9 B) 36
C) 81 D) 144
 
Answer & Explanation Answer: C) 81

Explanation:

729 = 9 x 9 x 9

=> Cube root of 729 = 9

 

Now, required square of 9 = 9 x 9 = 81.

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Filed Under: Square Roots and Cube Roots
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4 4832
Q:

Althaf borrows Rs. 1500 from two moneylenders. He pays interest at the rate of 12% per annum for one loan and at the rate of 14% per annum for the other. The total interest he pays for the entire year is Rs. 186. How much does he borrow at the rate of 12% ?

A) Rs. 300 B) Rs. 400
C) Rs. 1200 D) Rs. 1100
 
Answer & Explanation Answer: C) Rs. 1200

Explanation:

Let Althaf lent Rs. A at 14% per year.
Hence, Money lent at 12% = (1500-A);
Given, total interest = Rs. 186.
{(A x 14x 1)/100} + {[(1500-A) x 12 x 1/100]} = 186;
14A/100 + (18000 -12A)/100 = 186;
14A + 18000 - 12A = 186x100;
2A = 18600-18000;
A = 600/2 = Rs. 300.
Hence, money lent at 12% = 1500-300 = Rs. 1200.

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Filed Under: Simple Interest
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1 4828
Q:

In how many different ways can the letters of the word 'ABYSMAL' be arranged ?

A) 5040 B) 3650
C) 4150 D) 2520
 
Answer & Explanation Answer: D) 2520

Explanation:

Total number of letters in the word ABYSMAL are 7

 

Number of ways these 7 letters can be arranged are 7! ways

 

But the letter is repeated and this can be arranged in 2! ways

 

Total number of ways arranging ABYSMAL = 7!/2! = 5040/2 = 2520 ways.

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Filed Under: Permutations and Combinations
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