Quantitative Aptitude - Arithmetic Ability Questions

Volume of the block = (6 x 12 x 15) cu.cm = 1080 cu.cm 

Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm 

                                   = 3 cm.

Volume of this cube  = (3 x 3 x 3) cu.cm = 27 cu.cm 

Number of cubes =108027 = 40.

Each of the integers in the first set could be combined with any from the second set, giving a total of 4 x 5 = 20 possible pairs.

Of these the combinations that could give a sum of 23 are (5 + 18), and (9 + 14)

This means that the probability of getting a sum of 23 is 2/20 = 1/10

The given number series is 

71      88       113       150       203          277

   +17    +25       +37      +53        +74

        +8      +12        +16       +21

            +4          +4         +5

The series should be  71  88  112   150    203   276 i.e, the differences of the difference should be +4.

Hence, the odd man in the given series is 277.

3A = 4B = 7C = k,Then A = k/3, B = k/4 and C= k/7.

A : B : C = k/3 : k/4 : k/7 = 28:21 :12.

Cs share = Rs. [427 x (12/61)] = Rs. 84

x weeks x days = (7x + x) days = 8x days.