Quantitative Aptitude - Arithmetic Ability Questions

Rate of rice of quantity 280 kg = Rs. 15.60/kg

Rate of rice of quantity 120 kg = Rs. 14.40/kg

He want to earn a profit of Rs. 10.45/kg

Rate of Mix to sell to get profit of 10.45 =  

$$\begin{gathered} 280 x 15.60 + 120 x 14.40280 + 120 + 10.45 \\ 4368 + 1728400 + 10.45 \\ => 15.24 + 10.45 \\ = 25.69 \end{gathered}$$

CP of bullock and cart = 1800

Let price of bullock be x and cart be (1800 –x)

SP of bullock and cart = 1800 + 155/6 X 1800 = 2265

Also, 1.2x + 1.3 (1800 –x) = 2265

⇒1.2x –1.3x = -75

⇒x = 750

n(S) = C252 = 1326

 Let  A = event of getting both red cards

and B = event of getting both queens

then A∩B = event of getting two red queens

n(A) = C226 = 325,   n(B) = C24 = 6

 n(A∩B)=C22=1

 ∴ PA=3251326, PB = 61326

 PA∩B=11326

∴P ( both red or both queens) = PA∪B

= PA+PB-PA∩B=3251326+1221-11326=55221

Time taken to fill 2/7 = 1
Then to fill full 1 = ?
? = 1/(2/7) = 7/2 minutes.

Let 'Y' be the youngest player.

The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways.

The required number of ways = 3(3!) = 4320.

Given letters are k, l, m, n, o = 5

number of letters to be in the words = 3

Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters = 5P3 ways.

⇒ 5P3 = 5 x 4 x 3 = 60 words.

Let the second & third numbers are 2x & 3x respectively.
ATQ,
5x*6x = 4320
30*x*x = 4320
x*x = 144
x=12
Hence, second number = 5x = 5*12 = 60
Third number = 6x = 6*12 = 72
Ratio of first & second number = ¾
Hence, first number = ( ¾)*60 = 45
Sum of these 3 numbers = 60+72+45 = 177

Let the monthly salary of Shankar be = Rs.x
Amount invested on expenditure = 25% = x/4;
Remaning amount = 3x/4;
Amount invested on children education = 20% i.e = 3x/20;
Remaining amount = 3x/4 - 3x/20 = 3x/5;
Remaining amount invested in three different schemes i.e is 1/3(3x/5)
=> x/5 = 5600
Therefore x = 28000
Hence, Monthly salary of Shankar is Rs. 28,000.