Quantitative Aptitude - Arithmetic Ability Questions

Slant surface of a pyramid=1/2 perimeter of base slantheight

=1/2 x (4  x Side of squarebase) x Slantheight

Number of runs made by running = 180 - (11 x 4 + 8 x 6)
= 180 - (92)
= 88
Now, we need to calculate 88 is what percent of 180.
⇒88180×100  = 48.888%.

16x8 : Px4 = 5:2

P = 12.8 => Rs.12,800

Perimeter of the rectangle is given by 3000/10 = 300 mts

But we know,

The Perimeter of the rectangle = 2(l + b)

Now,

2(8x + 7x) = 300

30x = 300

x = 10

Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.

CP of bullock and cart = 1800

Let price of bullock be x and cart be (1800 –x)

SP of bullock and cart = 1800 + 155/6 X 1800 = 2265

Also, 1.2x + 1.3 (1800 –x) = 2265

⇒1.2x –1.3x = -75

⇒x = 750

Let father's age be x year and son's age be y year.

According to question,

2(x+y) = 8y _______(I)

and (x+y)/2 = 30

=> x+y = 60 years__________(II)

From equation (I) and (II)

8 y = 120

y = 15 years,

Hence x = 45 years.

Ans. 
Let B’s investment = x rs.
∴ A’s investment =( x + 1200) rs.
Ratio of the profits of A and B = (x+1200)*(15+4):x*15 = {19(x+1200)}:15x
Now,let the total profit of A =y
∴ total profit of B = (y-280)
But total profit = 1240
⇒y+(y-280)=1240
⇒2y=1520
⇒y= 760
∴profit of A = 760rs.
Profit of B = 760-280=480 rs.
Ratio of profits= 760:480 = 19:12
According to the question,

19(x+1200)/15x = 19/12

12x+14400 = 15x

⇒3x = 14400
⇒x = 4800 rs.
⇒investment of A = 4800+1200
                          = 6000 rs.

Given letters are k, l, m, n, o = 5

number of letters to be in the words = 3

Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters = 5P3 ways.

⇒ 5P3 = 5 x 4 x 3 = 60 words.