Quantitative Aptitude - Arithmetic Ability Questions

A completed their work in 8 X 2 = 16 days

B completed their work in 8 X 3 = 24 days

A and B one day work1/16 + 1/245/48

A and B completed their work in 48/5 days = 9.6 days

10C5 x 28C1 x 10C6 = 7266

Except Horse, remaining all belong to female category.

Hind - Female Deer

Ewe - Female Sheep

Bitch - Female Dog. 

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$$\begin{gathered} Wavers 4:8 \\ Days 4:8 \end{gathered}$$  :: 4:x

 4 x 4 x x = 8 x 8 x 4

=> x= 8*8*44*4

=>  x = 16.

L's 10 days work = 115×10=23

Remaining work = 1-23=13

Now,  work is done by K in one day = 1/18

1/3 work is done by K in  18×13 = 6 days

Three digit number will have unit’s, ten’s and hundred’s place.

Out of 5 given digits any one can take the unit’s place.

This can be done in 5 ways. ...              (i)

After filling the unit’s place, any of the four remaining digits can take the ten’s place.

This can be done in 4 ways. ...              (ii)

After filling in ten’s place, hundred’s place can be filled from any of the three remaining digits.

This can be done in 3 ways. ... (iii) 

So,by counting principle, the number of 3 digit numbers = 5x 4 x 3 = 60

For a triangle, we need 3 non-collinear points. So with 12 points (when all the 12 are such that any three non-collinear is12C3. But among them 8 points are collinear.

If all these 8 points are different we get 8C3 triangles as they are collinear.

In 12C3 triangles, we do not get 8C3 triangles

Therefore, The number of triangles we get = 12C3-8C3 = 164

P=F1+in