Quantitative Aptitude - Arithmetic Ability Questions

Given   1.21x0.91.1x0.11

= 1.21x100x0.9x101.1x10x0.11x100

= 9

= 3.

Let speed of train B be x m/s And length of train B be y m
Then length of train A is 2y m
Speed of train A = 84 × 5/18 = 210/9 m/s = 70/3 m/s
A.T.Q, (2y+y)/10 = 70/3 − x .............(i)
and (2y+y)/ 22.5 = 70/3 − 2x ................(ii)
solving (i) and (ii), y = 50 m

Ratio of milk and water = 2 : 1
Quantity of milk = 60 X 2/3 = 40 litre
Quantity of water = 20 litre
To make ratio, 1: 2, we have to double the water that of milk
So, water should be 80 litre.
That means 80 – 20 = 60 litre water to be added.

Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , then
w + x + y = 43 x 3 = 129 ---(i) and
w + y + z = 49 x 3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)
Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.
Therefore, Krish age is 36 years.

K's 1 day's salary = 1/10
L's 1 day's salary = 1/15
Together their 1 day's salary = 1/10 + 1/15
= 3/30 + 2/30
= 5/30
= 1/6
So the money will be enough for paying them both for 6 days.

 The formula to find the volume is given by just multiplying Length, Breadth and Height of that object. 

 Thus, V = L x B X H  

Volume Formulae :   

1. Volume of Cube of side 's' = s x s x s = s3  cubic units.   

2. Volume of Cylinder = πR2h cubic units.  

[Where R is Radius and h is height]

We have P = 15 000, r = 0.07 and since the actual date the loan was taken out
is not given, we use t =7/12

I = Prt=$15 000* 0.07* 7/12 = $612.50

Amount repaid = Future or accumulated value,

S = P + I = $15 000 + $612.50 = $15 612.50

Ans. C.
Let 4 consecutive even numbers are x, x+ 2, x+ 4, x+ 6
According to the question -
1/x + 1/x+2 = 11/60
x+2+x/ x(x+2) = 11/60
2(x+1)/x^2 + 2x = 11/60
120x + 120 = 11x 2 + 22x
11x 2 - 98x – 120 = 0
So ,
X = -24/22 , 10
X = -12/11 , 10
So, the numbers will be 10,12,14,16.
Hence,
Third largest number = 14
Reciprocal of third number = 1/14