Quantitative Aptitude - Arithmetic Ability Questions

For an income of Rs. 756, investment = Rs. 9000. 

For an income of Rs.212,  investment =Rs.9000756×212 = Rs. 125.

For a Rs. 100 stock, investment = Rs. 125.

Market value of Rs. 100 stock = Rs.125-14= Rs. 124.75

As water costs free, water sold at cost price of milk gives the profit.

Required profit % = 5/20 x 100 = 5 x 5 = 25%.

P(heart cards)=13/52

P(diamond cards)=13/52

P(heart or diamond)=13/52+13/52=1/2

Here I converted the original fraction to a fraction with the denominator being 10, because decimals can be written in the tenths place.

$$\begin{gathered} Divide numerator and denominator with '2' \\ 15 x 22 \\ = 210 \\ = 0.2 \end{gathered}$$

i=j/m

Here to say which fraction is greater from the given options, the fraction with greater numerator with same denominator or smaller denominator with same numerator.

To find the greater fraction, among the given options, make the denominators same for the options by finding the LCM of all the denominators.

7/12, 9/16, 13/20, 32/80

Now, LCM of 12, 16, 20, 80 = 240.

Then,

140/240, 135/240, 156/240, 96/240

Here 

$$\begin{gathered} 156240 > 140240 > 135240 > 96240 \\ => 1320 > 712 > 916 > 3280 \end{gathered}$$

Hence, largest fraction = 13/20.

Price of 1kg fresh cashew = Rs.120
Therefore, price of 10kg = Rs.120 x 10 = Rs.1200

10% of 10kg which eaten by rodents = 10 x 10/100 = 1kg.

So, End of Year he had 10kg - 1kg = 9kg

So, he sells that 9kg with Rs.20 per kg profit = 9 x 140 = 1260.

He buy 10kg wooden box with cashew for Rs.1200 and sell that for Rs. 1260

So, profit = 1260 - 1200 = Rs.60 more money he get.