Quantitative Aptitude - Arithmetic Ability Questions

Let the profit be Rs. p

Then Cost price of the bag = 340p/100 = 3.4p

According to question,

3.4p + p = 1540

4.4p = 1540

p = 1540/4.4

p = 350

The profit p = Rs, 350

Hence, The cost price of the bag = 3.4p = 3.4 x 350 = Rs. 1190.

Let man invested Rs. A And, after two years amount invested = (A +

Here I converted the original fraction to a fraction with the denominator being 10, because decimals can be written in the tenths place.

$$\begin{gathered} Divide numerator and denominator with '2' \\ 15 x 22 \\ = 210 \\ = 0.2 \end{gathered}$$

The numbers 0,1,2,3,4,5,6,7,8,9 are 10 in number while preparing telephone numbers any number can be used any number of times.

This can be done in 105ways, but '0' is there

So, the numbers starting with '0' are to be excluded is 94 numbers.

 Total 5 digit telephone numbers = 105- 94 = 3439

Cash price = $3695

Deposit =1/3 of $3695 = $1231.67

Loan amount = $3695.00 − $1231.67 = $2463.33

Total cost of loan = $25.97 × 104= $2700.88

Interest charged = total amount − loan
I = A − P
= 2700.88 − 2463.33
= 237.55

M = p(1+i)^n

Relative speed = 68-8 = 60 km/hr = 60 X 5 / 18 m/s = 50/3 m/s

Total distance = 150 m

Time taken to pass a man running in same direction = 150 X 3/50 = 9 seconds

Ratio in which the profit will divide – 23:15. Let theprofit be P

Now, [(23/38) - (15/38)] x (60/100) x P = 500

P = 3958.34