6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a single throw with 2 dices, what is probability of neither getting an even number on one and nor a multiple of 3 on other?

A) 11/36	B) 25/36
C) 5/6	D) 1/6

Answer & Explanation Answer: B) 25/36

Explanation:

We first calculate the probability of getting an even number on one and a multiple of 3 on other,Here, n(s) = 6x6 = 36 and

E = (2,3) (2,6) (4,3) (4,6) (6,3) (6,6) (3,2) (3,4)(3,6) (6,2)(6,4)

n(E) = 11P(E) = 11/36Required probability = 1-11/36 = 25/36

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Filed Under: Probability
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16 2650

Q:

Read the data given and answer the following questions

In a class of 60 students:

42 like Maths,

32 like English,

12 like neither Maths nor English

How many students like exactly one subject?

A) 16	B) 12
C) 6	D) 22

Answer & Explanation Answer: D) 22

Explanation:

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Filed Under: Percentage
Exam Prep: Bank Exams

0 2644

Q:

Consider a regular hexagon ABCDEF. Two towers are situated at B and C. The angle of elevation from A to the top of the tower at B is 30 deg, and the angle of elevation to the top of the tower at C is 45 deg. What is the ratio of the height of towers at B and C?

A) 1:√3	B) 1:3
C) 1:2	D) 1:2√3

Answer & Explanation Answer: B) 1:3

Explanation:

Let the side of regular hexagon be ‘a’

Let height of the tower 1 be h1 and tower 2 be h2

Height of tower 1 = h1 = (distance between A and B)* (tan 30o)= a.1/√3

Distance between A and C = 2*√3.a/2= √3a

Height of tower 2 = h2 = (distance between A and C)* (tan 45o) = √3a.1 = √3a

Ratio of height of towers at B and C respectively =a/√3/√3a = 1/3.

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Filed Under: Simplification
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3 2643

Q:

The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?

A) 333 sq.mts	B) 330 sq.mts
C) 362 sq.mts	D) 432 sq.mts

Answer & Explanation Answer: D) 432 sq.mts

Explanation:

Let the breadth of the rectangle = b mts

Then Length of the rectangle = b + 6 mts

Given perimeter = 84 mts

2(L + B) = 84 mts

2(b+6 + b) = 84

2(2b + 6) = 84

4b + 12 = 84

4b = 84 - 12

4b = 72

b = 18 mts

=> Length = b + 6 = 18 + 6 = 24 mts

Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts

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Filed Under: Area
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20 2638

Q:

The ages of Sunil and Anil are in the ratio 8:7, after 6 years, the ratio of their ages will be 19 : 17. What is the difference in their present ages?

A) 10 years	B) 6 years
C) 8 years	D) 4 years

Answer & Explanation Answer: D) 4 years

Explanation:

suppose the ages of Sunil and Anil are 8x yr and 7x yr, respectively.
After 6 yr, = 136x + 102 = 133x + 114
136x – 133x = 114 – 102
3x = 12 X = 12/3 = 4
Age of Sunil = 8x = 8 × 4 = 32 yr
Present age Anil = 7x = 7 × 4 = 28 yr
Required difference = (32 – 28) = 4 yr

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Filed Under: Problems on Ages
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3 2637

Q:

Calculate the future value of $3,000 invested at 7% for 5 years

A) 4207.66	B) 5207
C) 4376	D) 5687

Answer & Explanation Answer: A) 4207.66

Explanation:

F=P(1+i)^n

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

2 2634

Q:

select the letter missing from the following series.

U, O, I, ?,A

A) D	B) Q
C) p	D) E

Answer & Explanation Answer: D) E

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

0 2632

Q:

A farmer buys a goat and a sheep for Rs 3500. He sold the sheep at a profit of 20 percent and the goat at a loss of 10 percent. If he sold both the animals at the same price, then the cost price (in Rs) of the cheaper animal was?

A) 2000	B) 1500
C) 1750	D) 2250

Quantitative Aptitude - Arithmetic Ability Questions

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