6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:

A) 12	B) 60
C) 72	D) 90

Answer & Explanation Answer: B) 60

Explanation:

Volume of water displaced = (3 x 2 x 0.01) = 0.06 cu.m.

Mass of man = Volume of water displaced x Density of water

= (0.06 x 1000) kg

= 60 kg.

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Filed Under: Volume and Surface Area

0 3850

Q:

Agra and Delhi are 160 km apart. A train leaves Agra for Delhi and at the same time another train leaves Delhi for Agra. Both the trains meet 5 hrs after they start moving. If the train travelling from Agra to Delhi travels 6 km/hr faster than the other train, find the speed of the faster train?

A) 19 kmph	B) 13 kmph
C) 7 kmph	D) 9 kmph

Answer & Explanation Answer: A) 19 kmph

Explanation:

Let the speed of the slower train = p kmph

ATQ,

Speed of the faster train = (p + 6) kmph

Then,

(p + p + 6) x 5 = 160

10p + 30 = 160

10p = 130

p = 13 kmph

Then, speed of the faster train = p + 6 = 13 + 6 = 19 kmph.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

8 3850

Q:

In an election between two candidates, the winning candidate got 70% of the valid votes and won by a majority of 9000 votes. If out of total votes polled 90% votes are valid, then what is the total number of votes polled?

A) 30000	B) 25000
C) 22500	D) 27000

Answer & Explanation Answer: B) 25000

Explanation:

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Filed Under: Percentage
Exam Prep: Bank Exams

29 3847

Q:

5% of 40,000 is

A) 20000	B) 2000
C) 200	D) 20

Answer & Explanation Answer: B) 2000

Explanation:

5% of 40,000 = $\frac{5}{100} \times 40, 000 = 5 \times 400 = 2, 000$

Hence, 5% of 40,000 = 2,000.

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Filed Under: Percentage
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

7 3840

Q:

The B.D. and T.D. on a certain sum is Rs.200 and Rs.100 respectively. Find out the sum.

A) Rs. 400	B) Rs. 300
C) Rs. 100	D) Rs. 200

Answer & Explanation Answer: D) Rs. 200

Explanation:

$F = \frac{B D \times T D}{B D - T D} = \frac{200 \times 100}{200 - 100} = \frac{200 \times 100}{100} = R s . 200$

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Filed Under: Banker's Discount

1 3840

Q:

A man’s average monthly expenditure for the first four months of the year was Rs. 231.25. For the next five months, the average monthly expenditure was Rs. 22.75 more than what it was during the first four months. If the person spent Rs. 605 in all during the remaining three months of the year, find what percentage of his annual income of Rs. 3500 did he save in the year?

A) 10%	B) 15%
C) 20%	D) 25%

Answer & Explanation Answer: C) 20%

Explanation:

A man's average monthly expenditure for the first four months of the year = Rs.231.25.
For four month = 231.25 * 4 = Rs. 925
For next five month he spend = 231.25 + 22.75 for one month.
In five month he spend = (231.25 + 22.75) X 5 = 1270
If the person spent Rs. 605 in all during the remaining three months of the year,
Total expense = 925+1270+605= 2800
Saving = 3500-2800 = 700
% saving = 700/3500 * 100 = 20%

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Filed Under: Percentage
Exam Prep: Bank Exams

1 3838

Q:

Anmol soldtwo items for Rs 1000 each. On one, he gained 10% and on other, he lost 10%. How much did he gain or lose in the whole transaction?

A) profit,0.95%	B) loss,1%
C) profit,10%	D) loss,10%

Answer & Explanation Answer: B) loss,1%

Explanation:

Let the two item be A and B.

Cost price of A be x and cost price of B be y.

A sold for Rs 1000 on 10 % gain = 1.1x =1000

x= 1000/1.1 = 909.09

B sold for Rs. 1000 on 10% loss = 0.9y =1000y= 1000/0.9 = 1111.11

Total cost price of A and B = 2020.20

Selling price of A and B = 2000

Loss % = (2020.20 –2000)/2000 X 100

= 1.01 % loss

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Filed Under: Profit and Loss

3 3837

Q:

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ?

A) 205	B) 194
C) 209	D) 159

Answer & Explanation Answer: C) 209

Explanation:

We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys).

Required number of ways = ( ${}^{6}C_{1} \times {}^{4}C_{3}$ ) + $({}^{6}C_{2} \times {}^{4}C_{2})$ + ( ${}^{6}C_{3} \times {}^{4}C_{1}$ ) + ( ${}^{6}C_{4}$ )

= (24+90+80+15)

= 209.

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

7 3830

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