6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Tushar takes 6 hours to complete a piece of work, while Amar completes the same work in 10 hours. If both of them work together, then what is the time required to complete the work?

A) 3 hours	B) 3 hours 15 minutes
C) 3 hours 30 minutes	D) 3 hours 45 minutes

Answer & Explanation Answer: D) 3 hours 45 minutes

Explanation:

Let them take x hours working together

1/x = 1/10 + 1/6 = 8/30

X= 30/8 hours = 15/4 hours = 3 hours 45 minutes

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Filed Under: Time and Work
Exam Prep: Bank Exams

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Q:

The ratio of present ages of Sheetal and Divya is 6 : 5. After 8 years, their ages will be in the ratio of 22 : 19. What is the present age (in years) of Divya?

A) 22	B) 38
C) 34	D) 30

Answer & Explanation Answer: D) 30

Explanation:

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Filed Under: Problems on Ages
Exam Prep: Bank Exams

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Q:

One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.

A) 1/3	B) 1/2
C) 1/4	D) 1/6

Answer & Explanation Answer: B) 1/2

Explanation:

Total number of elementary events = 52

There are 26 red cards,out of which one red card can be drawn in $26 C_{1}$ ways =26.

So,required probability = 26/52 = 1/2

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Filed Under: Probability

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Q:

Rs 60500 is divided among A, B and C such that A receives 2/9 as much as B and C together and B receives 3/7 of as much as A and C together. What is the share of C (in Rs)?

A) 29850	B) 30120
C) 31350	D) 37250

Answer & Explanation Answer: C) 31350

Explanation:

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Filed Under: Partnership
Exam Prep: Bank Exams

11 3368

Q:

In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ?

$A) \frac{1}{3}$

$B) \frac{8}{21}$

$C) \frac{6}{21}$

$D) \frac{20}{21}$

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: A) Option A

Explanation:

Total number of flowers = (8+7+6) = 21.

Let E = event that the flower drawn is neither red nor green.

= event taht the flower drawn is blue.

--> n(E)= 7

--> P(E)= $\frac{7}{21}$ = $\frac{1}{3}$

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

8 3366

Q:

The value of

$\left [ \frac{2^{n}+2^{n-1}}{2^{n+1}-2^{n}} \right ]$ is:

Answer

$\frac{2^{n} + \frac{2^{n}}{2}}{2 x 2^{n} - 2^{n}} = \frac{2^{n} (1 + \frac{1}{2})}{2^{n} (2 - 1)} = \frac{3}{2}$

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Subject: Numbers Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

20 3361

Q:

For a nominal interest rate of 8.4%, what is the compounding frequency if the periodic interest rate is:0.7

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: D) 12

Explanation:

i=j/m

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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Q:

A person divided a sum of Rs. 17,200 into three parts and invested at 5%. 6% and 9% per annum simple interest. At the end of two years, he got the same interest on each part of money. What is the money invested at 9%?

A) Rs. 3,200	B) Rs. 4,000
C) Rs. 4,800	D) Rs. 5000

Answer & Explanation Answer: B) Rs. 4,000

Explanation:

Let sum invested @ 5% be P1, @ 6% be P2 then @ 9% =17200-(P1+P2)

So according to question

P1*5*2/100 = P2*6*2/100 or P1 = (6/5) P2

Also P2*6*2/100 = [17200-(P1+P2)]*9*2/100

Or 2 P2 = [17200–(11/5)P2] * 3

Or (2 + 33/5)P2 = 17200 * 3

P2 = 17200 * 3 * 5 / 43 = 6000

So P1 = 6/5 P2 = 7200

So Sum invested @ 9% = 17200–(6000+7200) = Rs 4000

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Filed Under: Simple Interest
Exam Prep: Bank Exams

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Quantitative Aptitude - Arithmetic Ability Questions

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