Quantitative Aptitude - Arithmetic Ability Questions

I=prt

In circumcstances word there are 3C's, 2S's, I, U,R, T, A, N, E

Total = 13 letters

But last letter must be N

Hence, available places = 12

In that odd places = 1, 3, 5, 7, 9, 11

Owvels = 4

This can be done in 6P4 ways 

Remaining 7 letters can be arranged in 7!/3! x 2! ways

Hence, total number of ways = 6P4 x 7!/3! x 2! = 360 x 5040/12 = 1,51,200 ways.

Number = quotient x divisor + remainder;
so, here
number = 138 k + 26
=> (23 x 6k) + (23+3)
=> 23(6k+1)+3
so, remainder is 3.

Let each literature text book cost be Rs. X

Then, cost of mathematics text book = Rs. (X + 2)

ATQ,

5X = 38 + 3(X + 2)

5X = 38 + 3X + 6

2X = 44

X = 22.

Therefore, cost of each literature text book = Rs. X = Rs. 22.

And that of masthematics = X + 2 = Rs. 24.

According to BODMAS rule,

After multiplication only, addition is done.

Hence,

5 + 2 x 10 = 5 + 20 = 25.

i=j/m

FV=
PV(1+  i)^n

Total weight of 50 boys = 45 X 50 = 2250

Average weight of 49 boys = 44.9

Total weight of 49 boys = 44.9 X 49 = 2200.1

Weight of boy who left the class=2250–2200.1=49.9