Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the finance charge for an average daily balance of $8431.10 with monthly interest rate of 1.4%

A) 98.04 B) 88.04
C) 68.04 D) 118.04
 
Answer & Explanation Answer: D) 118.04

Explanation:

0.014*8431.10

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Q:

25 divided by 7

A) 3.571 B) 35.71
C) 0.351 D) 0.0357
 
Answer & Explanation Answer: A) 3.571

Explanation:

Here we have 25 divided by 7.

25 will not go directly in 7

Hence, we get the result in decimals.

25/7 = 3.571.

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Q:

Radha and Hema are neighbours and study in the same school. Both of them use bicycles to go to the school. Radha’s speed is 8 km/hr whereas Hema’s speed is 10 km/hr. Hema takes 9 minutes less than Radha to reach the school. How far is the school from the locality of Radha and Hema?

A) 5 km B)  5.5 km
C) 6 km D) 6.5 km
 
Answer & Explanation Answer: C) 6 km

Explanation:
Let the distance between be D km
Time taken by radha – Time taken by Hema = 9 mins
So D/8 – D/10 = 9/60 hrs
D = 6km
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Filed Under: Time and Distance
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Q:

The present ages of Pranay and Sai are in the ratio of 15 : 17 respectively. After 6 years, the respective ratio between the age of Pranay and Sai will be 9 : 10. What will be the age of Pranay after 6 years?

A) 42 B) 36
C) 30 D) 24
 
Answer & Explanation Answer: B) 36

Explanation:

Let present age of Pranay = 15p

That of Sai = 17p

ATQ,

15p + 6/17p + 6 = 9/10

=> 150p + 60 = 153p + 54

=> p = 2

Therefore, Age of Pranay after 6 yrs = 15 x 2 + 6 = 36 years.

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Filed Under: Problems on Ages
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Q:

A man sells two articles. The cost price of the first article is equal to the selling price of the second article. The first article is sold at a profit of 20% and the second articles is sold at a loss of 20%. What is the ratio of the selling price of the first article and the cost price of the second article?

A) 24 : 25 B) 25 : 24
C) 29 : 27 D) 27 : 29
 
Answer & Explanation Answer: A) 24 : 25

Explanation:
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Filed Under: Profit and Loss
Exam Prep: Bank Exams

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Q:

In a single throw with 2 dices, what is probability of neither getting an even number on one and nor a multiple of 3 on other?

A) 11/36 B) 25/36
C) 5/6 D) 1/6
 
Answer & Explanation Answer: B) 25/36

Explanation:

We first calculate the probability of getting an even number on one and a multiple of 3 on other,Here, n(s) = 6x6 = 36 and

E = (2,3) (2,6) (4,3) (4,6) (6,3) (6,6) (3,2) (3,4)(3,6) (6,2)(6,4)

n(E) = 11P(E) = 11/36Required probability = 1-11/36 = 25/36

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17 3238
Q:

 

A) 110 B) 220
C) 330 D) 440
 
Answer & Explanation Answer: C) 330

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

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Q:

21% of 500 + 31% of 1100 - 30% of 790 = ? 

A) 209 B) 290
C) 309 D) 390
 
Answer & Explanation Answer: A) 209

Explanation:

Given 21% of 500 + 31% of 1100 - 30% of 790 = ?

 

? = 21 x 5 + 31 x 11 - 3 x 79

? = 105 + 341 - 237

? = 446 - 237

? = 209.

 

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Filed Under: Percentage
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