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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

If the price of kerosene be raised by 11%, find by how much percent a house holder must reduce his consumption of kerosene so as not to increase his expenditure?

A) 11% B) 9.09%
C) 11.09% D) 8.25%
 
Answer & Explanation Answer: B) 9.09%

Explanation:

Let the price of kerosene be x and household
consumption be y.
Expenditure = xy
New cost of kerosene = 1.1x, let new household
consumption be z.
In order to not to increase expenditure,
xy = 1.1x * a
⇒ a= 10y/ 11
⇒ consumption should decrease by = 1/11 X 100 = 9.09%

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Filed Under: Percentage
Exam Prep: Bank Exams

2 3088
Q:

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 36 min, then the slower pipe alone will be able to fill the tank in ?

A) 85 min B) 92 min
C) 187 min D) 144 min
 
Answer & Explanation Answer: D) 144 min

Explanation:

Let the slower pipe alone fill the tank in x min.

Then, faster pipe will fill it in x/3 min.

1/x + 3/x = 1/36 

4/x = 1/36 => x = 144 min.
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Filed Under: Pipes and Cistern
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

7 3083
Q:

Shivam Industries installed a flour mill for Rs. 300,000 five years ago. If the fixed annual rate of depreciation is 5% and they sold the mill for Rs. 250,000 their gain/loss % is?

 

 

A) No gain - No loss B) Loss 10%
C) Gain 12.5% D) Gain 10%
 
Answer & Explanation Answer: D) Gain 10%

Explanation:

Given that mill worth originally =3ooooo

Depreciation for 1 yr =300000x5/100= Rs. 15000

Then, depreciation for 5yrs = Rs. 75000

Value after 5yrs = 300000 - 75000 = Rs. 225000

Given Selling Price of the mill = Rs. 250000

Sp > CP

Gain = 250000 - 225000 = Rs. 25000

Gain% = 25000/250000 x 100 = 10%.

 

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

2 3082
Q:

What is the value of (81 + 82 + 83 + ......... +130)?

A) 5275 B) 10550
C) 15825 D) 21100
 
Answer & Explanation Answer: A) 5275

Explanation:
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Filed Under: Numbers
Exam Prep: Bank Exams , CAT

16 3081
Q:

If a person repaid Rs. 22500 after 10 years of borrowing a loan, at 10% per annum simple interest find out what amount did he take as a loan?

A) 11,225 B) 11,250
C) 10,000 D) 7,500
 
Answer & Explanation Answer: B) 11,250

Explanation:

SI = PTR/100

SI = PX100/100

SI = P

So, Amount=P+SI=2P→22500 = 2P→P = 11250

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Filed Under: Simple Interest
Exam Prep: Bank Exams

4 3075
Q:

A student gets 22 marks more in French than what she got in German. Her German marks are 28% of the sum of her French and German marks. What are her French marks?

A) 14 B) 36
C) 18 D) 42
 
Answer & Explanation Answer: B) 36

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

7 3069
Q:

If a + b + c = 7/12, 3a – 4b + 5c = 3/4 and 7a – 11b – 13c = – 7/12, then what is the value of a + c?

A) 1/2 B) 5/12
C) 3/4 D) 1/4
 
Answer & Explanation Answer: B) 5/12

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

2 3069
Q:

What is the fourth proportional to 336, 288 and 161?

A) 184 B) 115
C) 138 D) 134
 
Answer & Explanation Answer: C) 138

Explanation:
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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

4 3061