Quantitative Aptitude - Arithmetic Ability Questions

Q:

C and D started a business by investing Rs 4000 and Rs 5000 respectively. After 3 months, C withdraws Rs 1000 while D invest Rs 1000 more after 6 months of the starting of business. At the end of the year C’s share is Rs 3900. What will be the total profit (in Rs) at the end of year?

A) 7800 B) 10500
C) 8400 D) 12200
 
Answer & Explanation Answer: B) 10500

Explanation:
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Q:

At 9.5% simple interest per annum a sum of money became Rs. 942 in 6 years. The sum initially invested was:

A) 600 B) 616
C) 626 D) 636
 
Answer & Explanation Answer: A) 600

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Q:

Train A takes 45 minutes more than train B to travel a distance of 450 km. Due to engine trouble speed of train B falls by a quarter, so it takes 30 minutes more than Train A to complete the same journey. What is the speed of Train A (in km/hr)?

A) 90 B) 120
C) 100 D) 110
 
Answer & Explanation Answer: C) 100

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Q:

If N = 1 + 11 + 111 + 1111 + ... +111111111, then what is the sum of the digit's of N?

A) 45 B) 18
C) 36 D) 5
 
Answer & Explanation Answer: A) 45

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Q:

What is the fourth proportional to 189, 273 and 153?

A) 117 B) 299
C) 221 D) 187
 
Answer & Explanation Answer: C) 221

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Q:

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = ?

A) 0 B) 2
C) 12 D) 10
 
Answer & Explanation Answer: C) 12

Explanation:

Given 

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1

Using BODMAS Rule,

As multiplication precedes addition, 1 x 0 = 0, 

Now, 10 + 0 + 1 + 1 = 10 + 2 = 12.

 

Hence, 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = 12.

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Q:

There is a square field of area ‘X’ square meters. A cylindrical ditch of radius 7 meters and depth 2 meters is dug, and the earth is taken out and spread over the remaining part of the square field, the height of square field which goes up by 0.77 meters. What is the value of ‘X’ ? 

A) 548 sq. m B) 524 sq. m
C) 518 sq. m D) 554 sq. m
 
Answer & Explanation Answer: D) 554 sq. m

Explanation:

Volume of the cylindrical ditch = πrxrh = 22/7 ×7×7×2 = 308 sq.m

Area of remaining field = (X −πrxr) sq.m

= (X − 154)

ATQ –

(X – 154) ×0.77 = 308

(X – 154) = 400

X= 554 sq.m

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Q:

What are the Multiples of 4?

Answer

The Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40 upto 40. Mutiples of 4 means which can be divided by 4 leaving remainder '0'.


Common Multiples of 4 & 6 are 12, 24, 36, 48, 60 upto 60.

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