6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

A) Rs. 258	B) Rs. 358
C) Rs. 458	D) Rs. 558

Answer & Explanation Answer: D) Rs. 558

Explanation:

Area to be plastered = $[2 (l + b) \times h] + (l \times b)$

= $[2 (25 + 12) \times 6] + (25 \times 12) = 744 s q . m$

Cost of plastering = $744 \times \frac{75}{100} = R s . 558$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

79 49489

Q:

Solve the following

23 - [23 - {23 - (23 - 23 + 23)}]

A) -1	B) 23
C) 1	D) 0

Answer & Explanation Answer: D) 0

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 49406

Q:

What should come in place of question mark (?) in the following question?

45% of 400+ √? = 56% of 750 - 40% of 350

A) 10000	B) 1000
C) 10201	D) 9801

Answer & Explanation Answer: A) 10000

Explanation:

45/100×400+√?=56/100 ×750 -40/100 ×350

180 + √? = 420 - 140 180 + √? = 280 √? = 280 - 180 √? = 100 ? = 1002 ? = 10000

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Filed Under: Percentage

1 49303

Q:

Compute of 15872/32/4 = ?

A) 142	B) 1984
C) 124	D) 1948

Answer & Explanation Answer: C) 124

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

2 49301

Q:

Find the Next Number in the given number series?

3, 10.5, 36.75, 128.625, ?

A) 450.187	B) 442.151
C) 441.231	D) 456.852

Answer & Explanation Answer: A) 450.187

Explanation:

Pattern is

3

3 x 3.5 = 10.5

10.5 x 3.5 = 36.75

36.75 x 3.5 = 128.625

128.625 x 3.5 = 450.187

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

9 49294

Q:

Find the odd man out from the given series?

8, 18, 56, 232, 1165

A) 18	B) 56
C) 232	D) 1165

Answer & Explanation Answer: B) 56

Explanation:

The given number series 8, 18, 56, 232, 1165

8

8 x 2 + 2 = 18

18 x 3 + 3 = 57 (not 56)

57 x 4 + 4 = 232

232 x 5 + 5 = 1165

Hence, the odd man in the given series is 56.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

2 49279

Q:

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is

A) 4	B) 6
C) 8	D) 12

Answer & Explanation Answer: A) 4

Explanation:

Let the required numbers be 33a and 33b.

Then 33a +33b= 528 => a+b = 16.

Now, co-primes with sum 16 are (1,15) , (3,13) , (5,11) and (7,9).

Therefore, Required numbers are ( 33 x 1, 33 x 15), (33 x 3, 33 x 13), (33 x 5, 33 x 11), (33 x 7, 33 x 9)

The number of such pairs is 4

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Filed Under: HCF and LCM

129 49174

Q:

Find the value of $\{{(216)}^{\frac{2}{3}} + {(36)}^{\frac{- 1}{2}}\}$

A) 216/6	B) 218/6
C) 215/6	D) 217/6

Quantitative Aptitude - Arithmetic Ability Questions

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