Quantitative Aptitude - Arithmetic Ability Questions

Q:

Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ?

A) 60% B) 40%
C) 50% D) 30%
 
Answer & Explanation Answer: B) 40%

Explanation:

Lets say shyam sells at 100,

 

Since Ram sells 25% cheaper than Shyam,

 

Therefor Ram sells at less than 25% of100 or 75 rs.

 

Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or

 

125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.

 

now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.

 

Hence Brams Good is 40% cheaper than that of Shyam's good.

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Filed Under: Percentage
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

77 39364
Q:

Assume 57 + 59 + 109 = 0, then find the value of 573 + 593 + 1093

 

A) 1099701 B) 1099601
C) 1099801 D) 1098701
 
Answer & Explanation Answer: A) 1099701

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 39306
Q:

What will come in place of question mark in the following equation ?

54.(?)3 + 543 + 5.43 = 603.26

A) 6 B) 1
C) 9 D) 8
 
Answer & Explanation Answer: D) 8

Explanation:

Let x + 543 + 5.43 = 603.26. Then, x = 603.26 - (543 + 5.43) = 603.26 - 548.43 =54.83

Missing digit = 8..

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Filed Under: Decimal Fractions

11 39254
Q:

ΔABC is right angled at B. If m∠C = 45 deg, then find the value of (cosecA - √3).

 

A) (4-√3)/2   B) √2-√3  
C) -√3/2 D) (√6-1)/√3
 
Answer & Explanation Answer: B) √2-√3  

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 39192
Q:

Calculate the value of x if 1 - x289 = 1517

 

A) 64 B) 44
C) 36 D) 54
 
Answer & Explanation Answer: A) 64

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 39142
Q:

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

A) 77 B) 88
C) 99 D) 110
 
Answer & Explanation Answer: A) 77

Explanation:

Product of numbers = 11 x 385 = 4235

 

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235  =>  ab = 35

 

Now, co-primes with product  35 are (1,35) and (5,7)

 

So, the numbers are ( 11 x 1, 11 x 35)  and (11 x 5, 11 x 7)

 

Since one number lies 75 and 125, the suitable pair is  (55,77)

 

Hence , required number = 77

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Filed Under: HCF and LCM

72 39122
Q:

I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialing the first four, then what is the chance of dialing the correct number?

A) 1/999 B) 1/1001
C) 1/1000 D) 4/1000
 
Answer & Explanation Answer: C) 1/1000

Explanation:

It is given that last three digits are randomly dialled. then each of the digit can be selected out of 10 digits in 10 ways.
Hence required probability =1103 = 1/1000

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Filed Under: Probability

28 39088
Q:

If a = 5 + 22 & b = 5 - 22, then find the value of a2 - b2.

 

A) 2 B) 4
C) 2√2 D) 4√2
 
Answer & Explanation Answer: D) 4√2

Explanation:
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Exam Prep: Bank Exams

0 39071