Quantitative Aptitude - Arithmetic Ability Questions

Q:

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:

A) 5 B) 10
C) 15 D) 20
 
Answer & Explanation Answer: C) 15

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75  => x = 15

Report Error

View Answer Report Error Discuss

Filed Under: Problems on Ages

154 37235
Q:

Read the data given below and answer the questions based on it.

 

In the CBSE Board exams last year, 53% passed in Biology, 61% percent passed in English, 60% in Social studies, 24% in Biology and English, 35% in English and social studies, 27% in Biology and social studies and 5% in none.

 

What is the ratio of percentage of students who passed in Biology and Social Studies but not English in relation to the percentage of students who passed in Social Studies and English but not Biology?

A) 5:7 B) 7:5
C) 4:5 D) 5:4
 
Answer & Explanation Answer: A) 5:7

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: Bank Exams

2 37071
Q:

A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?

A) Rs. 39000 B) Rs. 49000
C) Rs. 59000 D) Rs. 69000
 
Answer & Explanation Answer: C) Rs. 59000

Explanation:

Interest received by A from B = 10% of half of Rs.50000 = 10% of Rs. 25000 = Rs.2500.

Amount received by A per annum for being a working partner = 1500 x 12 = Rs.18000

Let 'P' be the part of the remaining profit that A receives as his share.

So,total income of A = (Rs.2500 + Rs.18000 + Rs. P )

Total income of B = only his share from the remaining profit = 'P', as  A and B share the remaining profit equally.

 

We know that income of A = Twice the income of B 

So, (2500 + 18000 + P ) = 2(P)

P = 20500

 

Thus, the total profit = 2P + Rs.18000

= 2(20500) + 18000 = Rs.59000.

Report Error

View Answer Report Error Discuss

Filed Under: Partnership

40 37026
Q:

A team of 8 persons joins in a shooting competition. The best marksman scored 85 points. If he had scored 92 points, the average score for the team would have been 84. The number of points, the team scored was :

A) 665 B) 657
C) 658 D) 678
 
Answer & Explanation Answer: A) 665

Explanation:

Let the total score be x.

(x + 92 - 85) / 8 = 84.

So,  x + 7 = 672   => x = 665.

Report Error

View Answer Report Error Discuss

Filed Under: Average

62 37019
Q:

If A is 40% less than B, then B is how much percentage more than A?

 

 

A) 72.33 B) 60
C) 40 D) 66.66
 
Answer & Explanation Answer: D) 66.66

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: Bank Exams

1 36977
Q:

A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?

A) m:25.50 w:27.50 B) m:27.50 w:22.50
C) m:26.50 w:27.50 D) m: 24.50 w:26.50
 
Answer & Explanation Answer: B) m:27.50 w:22.50

Explanation:

Let the daily wage of a man be Rs. x.

Then, daily wage of a woman = Rs. (x - 5).

Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=>  1000x = 27500 <=>  x = 27.50.

Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50.

Report Error

View Answer Report Error Discuss

Filed Under: Average

54 36748
Q:

A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ?

A) 5:3 B) 1:4
C) 4:1 D) 9:1
 
Answer & Explanation Answer: D) 9:1

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

 

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

 

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

 

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

 

The ratio of milk and water in the new mixture = 16:4 = 4:1

 

If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.

 

Amount of water removed = 2 liters.

 

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

 

Now 10 lts milk is added => total milk = 18 lts

 

The required ratio of milk and water in the final mixture obtained

 

= (8 + 10):2 = 18:2 = 9:1.

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

53 36555
Q:

10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?

A) 215 days B) 225 days
C) 235 days D) 240 days
 
Answer & Explanation Answer: B) 225 days

Explanation:

Given that

(10M + 15W) x 6 days = 1M x 100 days

=> 60M + 90W = 100M

=> 40M = 90W

=> 4M = 9W.

From the given data,

1M can do the work in 100 days

=> 4M can do the same work in 100/4= 25 days.

=> 9W can do the same work in 25 days.

=> 1W can do the same work in 25 x 9 = 225 days.

 

Hence, 1 woman can do the same work in 225 days.

Report Error

View Answer Report Error Discuss

45 36516